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kykrilka [37]
3 years ago
9

The tiger at the zoo ate 133 pounds of food in 7 days find the average change in the zoos tiger food supply each day

Mathematics
1 answer:
vfiekz [6]3 years ago
5 0

Which describes the effect of the transformations on the graph of ƒ(x) = x2 when changed to ƒ(x) = 3(x + 2)2 − 4?

A) stretched vertically, shifted left 2 units, and shifted down 4 units  

B) stretched vertically, shifted right 2 units, and shifted up 4 units  

C) compressed vertically, shifted left 2 units, and shifted down 4 units  

Eliminate

D) compressed vertically, shifted right 2 units, and shifted up 4 units

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Answer:

The quotient is 10x+16

The remainder is 28x²+10x+22

Step-by-step explanation:

Solution,

                              ___________________________

x^3 - 3x^2 + x - 2 ]    10x^4 - 14x^3 -  10x^2 +  6x  -  10   [ 10x + 16

                                 <u>10x^4 - 30x^3 + 10x^2 -  20x</u>

                                              16x^3   -  20x^2 + 26x  - 10

                                             <u> 16x^3  -  48x^2 + 16 x   - 32</u>

                                                            28x^2  +  10x  + 22

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3 years ago
Someone please help me this is geometry
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PEMDAS

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Find the highest common factor of and lowest common multiple of 60 and 150 using prime factors
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According to industry sources, online banking is expected to take off in the near future. The projected number of households (in
Airida [17]

Answer:

(a) The least-square regression line is: y=4.662+2.709x.

(b) The number of households using online banking at the beginning of 2007 is 31.8.

Step-by-step explanation:

The general form of a least square regression line is:

y=\alpha +\beta x

Here,

<em>y</em> = dependent variable

<em>x</em> = independent variable

<em>α</em> = intercept

<em>β</em> = slope

(a)

The formula to compute intercept and slope is:

\begin{aligned}        \alpha  &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}  \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        \end{aligned}

The values of ∑<em>X</em>, ∑<em>Y</em>, ∑<em>XY</em> and ∑<em>X</em>² are computed in the table below.

Compute the value of intercept and slope as follows:

\begin{aligned}        \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} =             \frac{ 68.6 \cdot 55 - 15 \cdot 218.9}{ 6 \cdot 55 - 15^2} \approx 4.662 \\ \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        = \frac{ 6 \cdot 218.9 - 15 \cdot 68.6 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 2.709\end{aligned}

The least-square regression line is:

y=4.662+2.709x

(b)

For the year 2007 the value of <em>x</em> is 10.

Compute the value of <em>y</em> for <em>x</em> = 10 as follows:

y=4.662+2.709x

  =4.662+(2.709\times10)\\=4.662+27.09\\=31.752\\\approx 31.8

Thus, the number of households using online banking at the beginning of 2007 is 31.8.

5 0
3 years ago
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