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xeze [42]
4 years ago
12

What is the coefficient in the expression 8x^2+1?

Mathematics
2 answers:
jekas [21]4 years ago
4 0

The coefficient is 8, because it is right next to the variable, x.

stealth61 [152]4 years ago
4 0

Answer:

8

Step-by-step explanation:

We have been given an expression 8x^2+1. We are asked to find the coefficient in the given expression.

We know that coefficient is a numerical or constant quantity that is multiplied by the variable in an algebraic expression.

We can see that for our given expression x^2 is a variable and it is multiplied by 8, therefore, the coefficient of our given expression is 8.

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Compute 1 + 2 + 3 + 4 + ... +48 +49 + 50.​
ad-work [718]

Answer:

1275

Step-by-step explanation:

This is an arithmetic series. The formula for this is Sₙ = (n/2)(a₁ +aₙ)d. a₁ is the first term, so here it is 1, and aₙ is the nth term, or the last term, which is 50 here, but we don't know n.

Now we have to use the equation for an arithmetic sequence to solve for n. A sequence would just be if there was not a last number and it went on forever. that equation looks like aₙ = a₁ + (n - 1)d. Now the only new variable is d, which is the common difference. You can find that by subtracting one term from the term before it, like 2-1 = 1, so d is 1.

We can now solve for n by plugging our numbers into the second equation, so 50 = 1 + (n - 1)1, we can distribute the 1 and to (n-1) and get 50 = 1 + n - 1. Now the ones will cancel and we are left with n = 50

Finally we can plug everything into our original equation and find Sₙ = (50/2)(1+50), which simplifies to Sₙ = 25(51), and Sₙ = 1275.

4 0
4 years ago
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Step-by-step explanation:

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