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Gre4nikov [31]
3 years ago
6

Given parallelogram ABCD, m\angle A=5x+18 and m\angle B=3x-6 find find m\ C

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0

Answer:

57

Step-by-step explanation:

Firstly, we will need to calculate what x is.

To calculate this, the important property of the parallelogram to use is that adjacent angles are supplementary.

This means A and B are supplementary while B and C are also supplementary

what we are trying to say is that they add up to be 180

Thus,

5x + 18 + 3x -6 = 180

8x +12 = 180

8x = 180-12

8x = 168

x = 168/8

x = 21

Thus, the measure of angle B is 3x-6 = 3(21) -6 = 63-6 = 57

Now, another important property of parallelograms is that opposite angles are equal. This means that angle B= C = 57

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The length of the rectangle is twice its width. Write and solve a system of linear equations to find the length L and width W of
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Answer:

The length is equal to 12 and the width is equal to 6.

Step-by-step explanation:

In order to find the values here, we start by setting the width equal to x. Now knowing this, we know that the length is twice that long. Therefore, the length would be equal to 2x. Now we can use the perimeter formula to solve the equation.

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Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

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x - 2(t - 1) + t = 2.  Simplify to get

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6 0
3 years ago
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