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3 years ago

Given parallelogram ABCD, m\angle A=5x+18 and m\angle B=3x-6 find find m\ C

Mathematics

1 answer:

WARRIOR [948]3 years ago

6 0

Answer:

Step-by-step explanation:

Firstly, we will need to calculate what x is.

To calculate this, the important property of the parallelogram to use is that adjacent angles are supplementary.

This means A and B are supplementary while B and C are also supplementary

what we are trying to say is that they add up to be 180

Thus,

5x + 18 + 3x -6 = 180

8x +12 = 180

8x = 180-12

8x = 168

x = 168/8

x = 21

Thus, the measure of angle B is 3x-6 = 3(21) -6 = 63-6 = 57

Now, another important property of parallelograms is that opposite angles are equal. This means that angle B= C = 57

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The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,

klasskru [66]

Given:

The scale factor is $s=\dfrac{1}{3}$ and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

$(x,y)\to (k(x-a)+a,k(y-b)+b)$

According to the given information, the scale factor is $\dfrac{1}{3}$ and the center of dilation is at (4,2).

$(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)$ ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

$C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)$

$C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)$

$C(-2,11)\to C'(-2+4,3+2)$

$C(-2,11)\to C'(2,5)$

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

$A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)$

From the given figure it is clear that the image of point A is (8,4).

$A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)$

On comparing both sides, we get

$\dfrac{1}{3}(m-4)+4=8$

$\dfrac{1}{3}(m-4)=8-4$

$(m-4)=3(4)$

$m=12+4$

$m=16$

And,

$\dfrac{1}{3}(n-2)+2=4$

$\dfrac{1}{3}(n-2)=4-2$

$(n-2)=3(2)$

$n=6+2$

$n=8$

Therefore, the coordinates of point A are (16,8).

5 0

3 years ago

When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year f

MA_775_DIABLO [31]

Answer:

Option D is the correct answer.

Step-by-step explanation:

Initial height = 4 feet

Given that the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.

Let the rate of growing each year be g.

After 6 years height of tree = 4 + 6g

After 4 years height of tree = 4 + 4g

At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.

That is

$4+6g=4+4g+\frac{4+4g}{5}\\\\4+6g=\frac{20+20g+4+4g}{5}\\\\20+30g=24+24g\\\\6g=4\\\\g=\frac{2}{3}ft/year$

Option D is the correct answer.

8 0

3 years ago

How to solve this equation algebraically: Y=2x+1<br> 3x+4y=26

AURORKA [14]

You can substitute what y is into the second equation, so:
3x + 4(2x + 1) = 26
3x + 8x + 4 = 26
11x + 4 = 26
- 4
11x = 22
÷ 11
x = 2

y = (2 × 2) + 1
y = 5 + 1
y = 5

So you get x as 2 and y as 5, I hope this helps!

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3 years ago

When x=8 and y=20 find y when x=42

ella [17]

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answer= y=120

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Step-by-step explanation:

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