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Diano4ka-milaya [45]
4 years ago
8

How do you simplify the following equation? √64x²

Mathematics
1 answer:
mr_godi [17]4 years ago
4 0
\sqrt{64 x^{2} }  
same thing as:
\sqrt{8*8*x*x}

there are two 8's and two x's in there so they can come out to give you the answer 8x
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10(2^×) + 7(3^×) = 6^× + 70​
Mkey [24]

Answer:

x = 2.81 and 2.096

Step-by-step explanation:

Given the expression

10(2^x) + 7(3^x) = 6^x + 70​

This can also be expressed as;

10(2^x) + 7(3^x) = (2*3)^x + 70

10(2^x) + 7(3^x) = 2^x*3^x + 70

Let a  = 2^x and b = 3^x

10a + 7b = ab + 70

10a + 7b - ab = 70

10a-ab + 7b - 70 = 0

a(10-b)+7(b-10) = 0

a(10-b)-7(10-b) = 0

a-7 = 0 and 10-b = 0

a = 7 and b = 10

Since a = 2^x

7 = 2^x

log 7 = log2^x

log7 = xlog2

x = log7/log2

x = 2.81

Similarly

10 = 3^x

log 10 = log 3^x

log 10 = xlog3

x = log 10/log 3

x = 1/0.4771

x = 2.096

Hence the values of x that satisfies the equation are 2.81 and 2.096

8 0
3 years ago
A doctor's office has a computer file showing the heights of 100 male patients of one of the doctors of the practice. the height
kumpel [21]
A) Yes. we don't have enough information so this can not be determined.
B) No, it would just be an outlier.
7 0
3 years ago
3/8n+5(n-6)=1 7/8n-2
ivann1987 [24]

Answer:

n = 112/13 = 8.615

Step-by-step explanation:

(3/8) n + 5n - 30 = (17/8)n - 2

(3/8)n +5n - (17/8)n = 30-2

(13/4)n = 28

n = 28 * 4/13

n = 112/13

n = 8.615

4 0
3 years ago
3. Which of the following objects does not have three dimensions?
aleksandrvk [35]
Line because a line is not 3-D
4 0
3 years ago
How do i do 3 part a ?
WINSTONCH [101]


In general the binomial expansion is


(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0


So in our case, because we want ascending powers of x we'll write,


(-3x + 1)^{11} =  {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9  + {11 \choose 3 } (-3x)^3 1^8 + ...


We need to calculate the binomial coefficients:


{11 \choose 0}  = 1


{11 \choose 1}  = 11


{11 \choose 2}  = \dfrac{11 \times 10}{2} = 55


{11 \choose 3}  = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165


(-3x+1)^{11} =  1 (-3x)^0 1^{11}  + 11(-3x)^{1} 1^{10}  + 55 (-3x)^2 1^{9}  + 165 (-3x)^3 1^8 + ...


(1-3x)^{11} =  1 -33 x + 495 3x^2 - 4455 x^3+ ...



6 0
3 years ago
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