Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.
To find : Area (ΔMNC)
Solution: In Δ ABC, right angled at C,
AC= 6 cm, BC= 8 cm
Using pythagoras theorem
AB² =AC²+ BC²
=6²+8²
= 36 + 64
→AB² =100
→AB² =10²
→AB =10
Also, AM:MN:NB=1:2.5:1.5
Then AM, MN, NB are k, 2.5 k, 1.5 k.
→2.5 k + k+1.5 k= 10
→ 5 k =10
Dividing both sides by 2, we get
→ k =2
MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm
As Δ ACB and ΔMNC are similar by SAS.
So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.
![\frac{Ar(ACB)}{Ar(MNC)}=[\frac{10}{5}]^{2}](https://tex.z-dn.net/?f=%5Cfrac%7BAr%28ACB%29%7D%7BAr%28MNC%29%7D%3D%5B%5Cfrac%7B10%7D%7B5%7D%5D%5E%7B2%7D)
But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]
→ Area(ΔMNC)=24÷4
→Area(ΔMNC)=6 cm²
Yes. 7/8=21/24 and 2/3=16/24.
Answer:
The answer is "
is not a perfect square".
Step-by-step explanation:
12 is not a perfect square because it is the natural number, and no other natural number would square the number 12, that's why it is not a perfect square.
If we calculate the square root of . so, it is will give 
that is not a perfect square root which can be described as follows:
is not a perfect square root.
Answer:
Step-by-step explanation:
slope, m = (6-0) /(0--2) = 6/2 = 3
intercept, c at y = -2 when x = 0
Equation
y = mx + c
y = 3x -2
Answer:
Sides/diagonals are congruent
Step-by-step explanation:
If the distance formula is used to determine the type of quadrilateral, then we are interested in knowing whether the opposite sides are congruent or adjacent sides are congruent.
We can also use the length of diagonals to determine which type of quadrilateral.
For instance the square has all sides equal.
The diagonals of the rectangle are congruent.
