Let x be the volume (liters) of pure (at 100%) acid needed
Let y be the volume (liters) of the other acid (at 10%) needed
The final solution will be:
a) x+ y = 63 liters, AND their respective concentration in acid: is
100% x & 10% :y that will generate 63 liters at 20%
b) x +0.1 y = 63x 0.2 = 12.6
Let's solve this system of 2 equations:
x + y =63
x + 0.1 y = 12.6
Solving it will give you:
x= 7 liters at 100%
y = 56 liters at 10%
The red pencil is 6 and the blue one is 3 so blue +blue(3+3)=6
1+1 = 2
So if it is 2 then 2+6 = 8
I hope this helped love
28 represents 100%
22 represents x %
X= 22•100/28=78.57142857%
