Answer:
~8.66cm
Step-by-step explanation:
The length of a diagonal of a rectangular of sides a and b is
in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:
Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths is
So the solution here is
9514 1404 393
Answer:
x = 5, x = 11
Step-by-step explanation:
Set f(x) = 0 and solve for x.
0 = (x -8)² -9
9 = (x -8)² . . . . . add 9
±√9 = x -8 . . . . . take the square root
±3 +8 = x . . . . . . . add 8
That is, ...
x = 8 -3 = 5 . . . . lesser x
x = 8 +3 = 11 . . . greater x
Type in the question without g(x)
C is the right answer because the period should be pi/(1/3), so the answer is 3pi