Help... me with this math...if you get it correct u get brainliest

Please follow the directions. Don't round immediate calculations. Please try to get it right

marin [14]

Answer:

well without rounding anything, I got 511.9999999992 people

Step-by-step explanation:

so the ratio I used was 36 people for every 225 people( 225 because in total he asked 225 people) then I divided 3,200 into 225 to see how many times It would fit, the answer was 14.2222222222 then I multiplied that by 36 and my answer was 511.9999999992 people. I hope this helps, I tried to be as accurate as possible.

4 0

3 years ago

The height of a cable that runs between two supports on a suspension bridge can be modeled by a quadratic function () where is t

Murrr4er [49]

What is the vertex

Its vertex is at (36, -10)

Let us assume that the left edge of the cable is at the origin.

Since the cable is at its lowest height 10 feet halfway between the two supports, the y-coordinate of its lowest point is -10 ft and the x coordinate is 72 ft/2 = 36 ft.

So, its vertex is at (36, -10)

Axis of symmetry

The y-axis.

Since the cable is symmetric about its lowest point, the axis of symmetry is the y-axis.

Domain

The domain is (0, 72).

Since the minimum value of its x-coordinate is at the origin which is x = 0 and the maximum value is at the other support which is at x = 72 ft,

the domain is (0, 72).

Range

The range is (0, -10)

Since the minimum value of the y-coordinate is -10ft and the maximum value is at the origin y = 0,

the range is (0, -10)

x and y-intercepts

The x-intercept is (0, 72) and the y-intercept is (0, 0)

Since the cable is attached at the origin and at 72 feet away from the origin at the other support, the x-intercept is 0 and 72 ft and the y-intercepts are 0 and 0.

So, the x-intercept is (0, 72) and the y-intercept is (0, 0)

Learn more about quadratic functions here:

brainly.com/question/10606041

5 0

2 years ago

Find a formula for the sum of the first n even positive integers.

melisa1 [442]

So even postive integers are by defention in form 2k where k is a natural number so
let the sum of even integers to n=S
S=2(1+2+3+4+5+6+7+8+......+k-1+k
divide bith sides of equation 1 by 2
0.5S=1+2+3+4+5+...........+k-1+k
S=2(k+(k-1)+..............................+2+1)
divide both sides of equation 2 by 2
0.5S=k+k-1+..............................+2+1)
by adding both we will get
___________________________
S=(k+1)(k)
so the sum will be equal to
S=
${k}^{2} + k$
so let us test the equation
for the first 3 even number there sums will be
2+4+6=12
by our equation 3^2+3=12
gave us the same answer so our equation is correct

7 0

3 years ago

PLEASE ANSWER ALL BIG REWARD

sleet_krkn [62]

Answer:

multiplying
similar figures
scale factor
(x, y) (–3x, –3y) and (x, y) (0.23x, 0.23y)
(x, y) --> (2x, 4y)
Need diagram
A. The line segment has become longer with endpoints D' (-12, -10) and E' (6 -8).
Need image
Reduction
Enlargement

good luck, i hope this helps :)

6 0

3 years ago

At most, how many unique roots will a third-degree polynomial function have?

beks73 [17]

The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.

In fact, if you use complex number, then a polynomial with degree n has exactly n roots.

So, in particular, a third-degree polynomial can have at most 3 roots.

In fact, in general, if the polynomial $p(x)$ has solutions $x_1,\ x_2,\ldots x_n$ , then you can factor it as

$p(x) = (x-x_1)(x-x_2)\ldots (x-x_n)$

So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as

$p(x)=(x-x_1)(x-x_2)(x-x_3)(x-x_4)$

But this is a fourth-degree polynomial.

7 0

3 years ago