525, I believe. Because each ticket is $5, and in total, the tickets were $105. So I multiplied 5 x 105=525.
Please correct me if I'm wrong.
To find those equations we can do any multiplication or division of both sides of the equation:
Examples:
2x + 9 = -15 | · 2
4x + 18 = -30
2x + 9 = -15 | · (-1)
-2x - 9 = 15
2x + 9 = -15 | ÷ 2
x + 4.5 = -7.5
There is the same solution: x = -12.
Answer:
<u>There are 70 students on the two buses, 42 on the large and 28 on the smaller.</u>
Step-by-step explanation:
1. Let's review the information provided to us to answer the question correctly:
Number of students on the large bus = 42
Number of students on the small bus = 40% of the students
2. How many total students are on the two buses?
For answering the question, we will use the Rule of Three Simple, this way:
42 students are 60% of total students, how much students are the 100%?
Total students = 42 * 100/60
Total students = 4,200/60 = 70
<u>There are 70 students on the two buses, 42 on the large and 28 on the smaller.</u>
Given that
(2/x)+(3/y) = 13--------(1)
(5/x)-(4/y) = -2 -------(2)
Put 1/x = a and 1/y = b then
2a + 3b = 13 ----------(3)
On multiplying with 5 then
10a +15 b = 65 -------(4)
and
5a -4b= -2 ----------(5)
On multiplying with 2 then
10 a - 8b = -4 -------(6)
On Subtracting (6) from (4) then
10a + 15b = 65
10a - 8b = -4
(-)
_____________
0 + 23 b = 69
______________
⇛ 23b = 69
⇛ b = 69/23
⇛ b =3
On Substituting the value of b in (5)
5a -4b= -2
⇛ 5a -4(3) = -2
⇛ 5a -12 = -2
⇛ 5a = -2+12
⇛ 5a = 10
⇛ a = 10/5
⇛ a = 2
Now we have
a = 2
⇛1/x = 2
⇛ x = 1/2
and
b = 3
⇛1/y = 3
⇛ y = 1/3
<u>Answer :-</u>The solution for the given problem is (1/2,1/3)
<u>Check</u>: If x = 1/2 and y = 1/3 then
LHS = (2/x)+(3/y)
= 2/(1/2)+3/(1/3)
= (2×2)+(3×3)
= 4+9
= 13
= RHS
LHS=RHS is true
and
LHS=(5/x)-(4/y)
⇛ 5/(1/2)- 4/(1/3)
⇛(5×2)-(4×3)
⇛ 10-12
⇛ -2
⇛RHS
LHS = RHS is true
