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UkoKoshka [18]
3 years ago
7

Plz help one number 9 plz, merci

Mathematics
1 answer:
charle [14.2K]3 years ago
4 0
I'm assuming bridge of nose is just midway between the eyes.  So if the cat's right eye is 3 inches from the bridge, then the left eye is 3 inches from the bridge.  So the cat's left eye is 6 inches from its right eye.
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Determine the number of solutions the system has. 2x = 2y -6 y = -x-1
guapka [62]

Answer:

(-2,-3) / one solution

Step-by-step explanation:

If you find my answer helpful, please consider marking it Brainliest

And if you still have any questions about the way I solved it, don't hesitate to ask me in the comments

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3 years ago
Solve by elimination <br> X - 6y + 2z = 5<br> 2x-3y+z=4<br> 3x + 4y - z = -2
Vesnalui [34]

Answer:

x=1

y=-3

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Step-by-step explanation:

6 0
2 years ago
The mean height of women in a country (ages 20-29) is 64 4 inches A random sample of 50 women in this age group is selected What
Simora [160]

Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 64.4 inches, standard deviation of 2.91

This means that \mu = 64.4, \sigma = 2.91

Sample of 50 women

This means that n = 50, s = \frac{2.91}{\sqrt{50}}

What is the probability that the mean height for the sample is greater than 65 inches?

This is 1 subtracted by the p-value of Z when X = 65. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{65 - 64.4}{\frac{2.91}{\sqrt{50}}}

Z = 1.46

Z = 1.46 has a p-value of 0.9279

1 - 0.9279 = 0.0721

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

8 0
2 years ago
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