I hope this helps you
4^3/3.x^2/3.y^3/3
4.y.x^2/3
Answer:
\\x= P/(c -d)[/tex],
Assume that the price of each minute in the first plan is $c and that the second plan charges a flat rate of $P and a charge of additional $d for every minute.
Step-by-step explanation
Assume that the price of each minute in the first plan is $c and that the second plan charges a flat rate of $P and a charge of additional $d for every minute.
Thus, the monthly cost of a customer who consumes x minutes in each plan is:
For the first plan: 
and for the second plan: 
Considering that the monthly costs must be the same in each plan, you have to:
![cx = P + dx\\ transposing terms\\cx - dx = P\\ applying common factor\\(c -d)x = P\\ dividing by [tex]c - d](https://tex.z-dn.net/?f=cx%20%3D%20P%20%2B%20dx%5C%5C%20transposing%20terms%3C%2Fp%3E%3Cp%3E%5C%5Ccx%20-%20dx%20%3D%20P%5C%5C%20%20%20applying%20common%20factor%3C%2Fp%3E%3Cp%3E%5C%5C%28c%20-d%29x%20%3D%20P%5C%5C%20dividing%20by%20%5Btex%5Dc%20-%20d)
\\x= P/(c -d)[/tex].
For example if
, Then the number of minutes would be,
and the total cost for each plan would be 
We want double sixes. This means that we want both the first roll and the second roll to be 6.
The given point is given as (r1 , r2) where:
r1 is output from first roll
r2 is output from second roll
Since we want both outputs to be 6, therefore, the answer would be: (6,6)
Answer:
7c+21
Step-by-step explanation:
multiply 7 by c and 7 times 3
7c and 21
7c+21
Answer:
)
Step-by-step explanation:
This system we can solve by substitution method :
y=13x-1
y=9x+4
_______
y=13x-1
13x-1=9x+4 (instead y in second equation we use 13x-1 and first rewrite)
_______
y=13x-1
13x-9x=4+1 (subtract 9x and add 1 for each side)
______
y=13x-1
4x=5 (divide by 4)
_____
y=13x-1
(instead x in first eq we write 5/4)
______
