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3 years ago

Consider the linear equation 2/5x+y=11. will you choose to fix x or y?

1 answer:

4 0

Y is the easiest to fix because it has no coefficient, and is therefore the easiest to set on the other side of the equation by itself

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One smartphone plan costs $52 per month for talk and messaging and $8 per gigabyte of data used each month. A second smartphone

valina [46]

Answer:

Both plans would cost $100 if 6 gigabytes of data are used.

Explanation:

From the question, the system of equation are correctly represented by using small letter c to represent the total cost in dollars for both equations as already assumed in the question as follows:

c = 52 + 8d ........................... (1)

c = 82 + 3d ........................... (2)

Since c is common to both, equations (1) and (2) can therefore be equated and d solved for as follows:

52 + 8d = 82 + 3d

8d - 3d = 82 - 52

5d = 30

d = 30 / 5

d = 6

Substituting d = 6 into equation (1), we have:

c = 52 + (8 * 6)

c = 52 + 48

c = 100

Since d = 6 and c = 100, it therefore implies that both plans would cost $100 if 6 gigabytes of data are used.

5 0

2 years ago

I need help with this math question pretty please

AleksAgata [21]

Just do 11x18x20x14 and u should get it

3 0

3 years ago

Read 2 more answers

What is the 33rd term of this arithmetic sequence?<br><br> 12, 7, 2, -3, -8, …

sergiy2304 [10]

The answer be negative 158 or -158

7 0

3 years ago

Please Help! My question is in the picture.

Varvara68 [4.7K]

First we need to determine the type of progression in the question.
That's geometric progression. Because the pattern from one sequence to the others are about multiplying.

Second, determine the ratio of the progression
r = a₂/a₁
r = a₂ ÷ a₁
r = 1/2 ÷ 2
r = 1/2 × 1/2
r = 1/4

Third, determine the formula to know the recursive rule
a₂ = a × 1/4
a₂ = 1/4 × a
$a_{n} = \frac{1}{4} a_{(n-1)}$

Fourth, determine a₁. a₁ is the first term of the progression
a₁ = 2

Final answer:
Recursive rule
$a_{n} = \frac{1}{4} a_{(n-1)}$
a₁ = 2

4 0

3 years ago

Maria is purchasing sandwiches for her team at work. Each sandwich costs $6.25 and there is a delivery fee of $15.00, all taxes

Oduvanchick [21]

Answer:

The maximum number of sandwiches she can buy is 24.

Step-by-step explanation:

We can create a function to represent the cost of her team's lunch in function of the number of people in the team. We have:

$cost(x) = 15 + 6.25*x$

Since she needs to stay on budget, the cost has to be less or equal to 170, therefore:

$cost(x) \leq 170\\15 + 6.25*x \leq 170\\6.25*x \leq 170 - 15\\x \leq \frac{155}{6.25}\\x \leq 24.8$

Since she can't buy 0.8 sandwiches, the maximum number of sandwiches she can buy is 24.

3 0

3 years ago