Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
Answer:
480
Step-by-step explanation:
8x4=32
8x8=64
32x4=128
32x8=256
256+128+64+32=480
X = 5; 2(5) - 1 = 9. 4(9) = 36
Hehehe I wish A lallaalalalal
1hour=60min
24hour=?
24hour=1440 min
1d=1440 min
4.8d=?
4.8 days =6956 hope you like my explanation
