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Marta_Voda [28]
3 years ago
6

The volume of a cube is 125 cubic inches. what is the length of one edge of the cube?

Mathematics
1 answer:
jeyben [28]3 years ago
8 0
V=S^3 (Volume is equal to the side cubed)
V=125
125=S^3 (Now cube root both sides to isolate your side, s)
5=S
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Find the following bases.
Oduvanchick [21]

Answer:

a.. 8% of ? = 20   <u> 240</u>

b.75% of ? = 30    <u>40</u>

c. 20% of ? = 45   <u>225</u>

d. 150% of ? = 36  <u>24</u>

The steps of  answer is in attached file

Hope it helps..

Have a great day : )

6 0
2 years ago
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If the code for CAB is DEK, what is the code for BED?
snow_tiger [21]

Answer:

CIM

Step-by-step explanation:

C is the 3rd letter of the alphabet, A is the 1st, and B is the 2nd.

CAB = 3,1,2

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DEK = 4,5,11

Comparing:

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BED = 2,5,4, so adding the corresponding numbers:

2+1 = 3

5+4 = 9

4+9 = 13

So the code is CIM.

7 0
3 years ago
How do you completely factor:<br><br> 2x^3 – 5x^2 – 22x + 55
DochEvi [55]

Answer:(X^2-11)(2X-5)

Step-by-step explanation:

2x^3-5x^2-22x+55

x^2(2x-5)-11(2x-5)

(X^2-11)(2X-5)

8 0
3 years ago
The savings account offering which of these APRs and compounding periods
Ann [662]

Answer:

The answer is "Option C"

Step-by-step explanation:

The using formula= (1+\frac{r}{n})^n -1

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→ n = compounded value

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When compounded is monthly 4.0784\%  

n = 12

\to (1+ \frac{0.040784}{12})^{12} = 1.0403-1 = 0.0403

In choice b:

When compounded is quarterly4.0792\%

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In choice c:

Whenn compounded is daily 4.0730 \%

n = 365\\\\\to (1+ \frac{0.040730}{12})^{365}  = 3.328-1 = 2.328

In choice d:

When compounded is semiannually4.0798\%

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7 0
2 years ago
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A box has a volume of 192 cubic inches, a length that is twice as long as its width, and a height that is 2 inches greater than
ruslelena [56]

Answer:

Therefore the dimension of the cuboid is 8 inches×4 inches ×6 inches.

Step-by-step explanation:

Cuboid : A cuboid is a three dimension shape. The length ,breadth and height of a cuboid are not same.

  • A cuboid has 6 faces.
  • A cuboid contains 8 vertices.
  • A cuboid contains 12 edges .
  • The total surface area of a cuboid is

           = 2(length×breadth+breadth×height+length×height) square units

  • The dimension of a cuboid is written as length×breadth×height.
  • The volume is( length×breadth×height) cubic units

Given that the volume of the box is 192 cubic inches.

Let x inches be the width of the cuboid.

Since the length is twice as long as its width.

Then length = 2x inches

Again height is 2 inches longer than width.

Then height = (x+2) inches.

Therefore the volume of the cuboid is

=[x\times 2x\times (x+2)]   cubic inches

=[2x^2(x+2)]     cubic inches

=(2x^3+4x^2)     cubic inches

According to the problem,

2x^3+4x^2=192

\Rightarrow 2x^3+4x^2-192=0

\Rightarrow 2(x^3+2x^2-96)=0

\Rightarrow (x^3+2x^2-96)=0

\Rightarrow x^3-4x^2+6x^2-24x+24x-96=0

\Rightarrow x^2(x-4) +6x(x-4)+24(x-4)=0

\Rightarrow (x-4)(x^2+6x+24)=0

Therefore x=4

Since the all zeros of x²+6x+24 =0 is negative.

Therefore breadth = 4 inches

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 and height = (4+2)inches = 6 inches.

Therefore the dimension of the cuboid is 8 inches×4 inches ×6 inches.

8 0
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