Compute the necessary values/derivatives of 
at 
:
Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) at by
###
Another way of doing this would be to solve for the coefficients 
in
by expanding the right hand side and matching up terms with the same power of 
.
Answer:
Question 1: y-11x+5 I think; Question 2: I'm not sure
Step-by-step explanation:
It is 4900mm^3 because there are 1000mm^3 in one 1cm^3.
If you do 10^3 (10 mm) it gives you 1000mm^3.
Hope this helps.
Answer:
9
Step-by-step explanation:
g(4)=4^2 =16, so we need to find f(16).
f(16)=16-7=<u>9</u>
.................................................
