This is a great question!
To determine the probability with which two sweets are not the same, you would have to subtract the probability with which two sweets are the same from 1. That would only be possible if she chose 2 liquorice sweets, 5 mint sweets and 3 humburgs -
As you can see, the first time you were to choose a Liquorice, there would be 12 out of the 20 sweets present. After taking that out however, there would be respectively 11 Liquorice out of 19 remaining. Apply the same concept to each of the other sweets -
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Calculate the probability of drawing 2 of each, add them together and subtract from one to determine the probability that two sweets will not be the same type of sweet!
<u><em>Thus, the probability should be 111 / 190</em></u>
The ratio would be 1:8
Change 2kg to g then simply
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Let y(t) represent the level of water in inches at time t in hours. Then we are given ...
y'(t) = k√(y(t)) . . . . for some proportionality constant k
y(0) = 30
y(1) = 29
We observe that a function of the form
y(t) = a(t - b)²
will have a derivative that is proportional to y:
y'(t) = 2a(t -b)
We can find the constants "a" and "b" from the given boundary conditions.
At t=0
30 = a(0 -b)²
a = 30/b²
At t=1
29 = a(1 - b)² . . . . . . . . . substitute for t
29 = 30(1 - b)²/b² . . . . . substitute for a
29/30 = (1/b -1)² . . . . . . divide by 30
1 -√(29/30) = 1/b . . . . . . square root, then add 1 (positive root yields extraneous solution)
b = 30 +√870 . . . . . . . . simplify
The value of b is the time it takes for the height of water in the tank to become 0. It is 30+√870 hours ≈ 59 hours 29 minutes 45 seconds
Answer:
16π
Step-by-step explanation:
Area of the larger circle:
πr²
π(5)²
25π
Area of the smaller circle:
πr²
π(3)²
9π
Subtract the two:
25π-9π=16π
Answer:
B) 53%
Step-by-step explanation:
To find the percent divide the number who will vote for Candidate A over the total number of people surveyed
vote for Candidate A/total surveyed
128/240=0.53333
0.53333*100=53.3333%
Rounded to the nearest percent=53%
Hope this helps! :)