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3 years ago

What are the GCF of 18 and 20

Mathematics

1 answer:

Fittoniya [83]3 years ago

4 0

Answer:

The greatest common factor (GCF) of 18 and 20 is 2.

Step-by-step explanation:

To solve this problem, first, you have to find the greatest common factor of 18 and 20.

Factors of 18:

1, 2, 3, 6, 9, and 18.

Factors of 20:

1, 2, 4, 5, 10, and 20.

So, the greatest common factor (GCF) of 18 and 20 is 2.

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you are going in vacation you want to visit 4 different places in 2 weeks and you don't care what order in which you visit them.

ankoles [38]

Answer:

no it's not possible

Step-by-step explanation:

because the bases of an exponential function and its equivalent logarithmic function are equal

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2 years ago

What is the beat values of averages, such as mean, median, and mode, are known as

IrinaVladis [17]

A) Standard deviation

3 0

3 years ago

The junior and senior students at Mathville High School are going to present an exciting musical entitled, "Math, What is it Goo

xeze [42]

Some parts are missing in the queston. Find attached the picture with the complete question

Answer:

$\large\boxed{\large\boxed{161}}$

Explanation:

Let's put the information in a table step-by step.

(number of remaining students)

Juniors Seniors

Condition

Initially J S

15 seniors left S - 15

Twice juniors as seniors 2(S - 15)

3/4 of the juniors left 1/4×2(S - 15)
1/3 of seniors left 2/3×(S - 15)

At the end, there were 8 more seniors than juniors:

2/3×(S - 15) - 1/4×2(S - 15) = 8

Now you have obtained one equation, which you can solve to find S, the number of senior students, and then the number of junior students.

Solve the equation:

$2/3\times (S - 15) - 1/4\times 2(S - 15) = 8$

Mutilply all by 12:

$8(S - 15)-6(S - 15)=96$

Distribution property:

$8S-120-6S-90=96$

Addtion property of equalities:

$8S-6S=96+120+90$

Add like terms:

$2S=306$

Division property of equalities:

$S=306/2=153$

That is the number of senior students that came out to the information meeting, but the number of students remaining to perform in the school musical is (from the table above):

$2/3\times (S-15)+1/4\times 2(S-15)$

Just substitute S with 153 fo find the number of students that remained to perfom in the musical:

$2/3\times (153-15)+1/4\times 2(153-15)\\ \\ 2/3(138)+1/2(138)$

$161$

5 0

3 years ago

1. 10(.15)=1.5

Fed [463]

Answer:

6.14125(0.15) = 0.9211875 (below 1)

6.14125 - 0.92118 = 5.22007

Step-by-step explanation:

Given data

1. 10(.15)=1.5

2. 10-1.5=8.5

3. 8.5 (.15)=1.275

4. 8.5-1.275=7.225

continuation the sequence

5) 7.225 (0.15) = 1.08375

6) 7.225 - 1.08375 = 6.14125

7) 6.14125(0.15) = 0.9211875 (below -one)

8 ) 6.14125 - 0.9211875 = 5.2200625 (get number 5)

9) 5.2200625(0.15) = 0.783009

10) 5.2200625 - 0.783009 = 4.4370532

3 0

3 years ago

ABCD is a quadrilateral inscribed in a circle, as shown below:

german

Answer:

A. (x + 16) + (6x − 4) = 180

Step-by-step explanation:

Inscribed quadrilateral has opposite angles supplementary.

So

m∠A + m∠C = 180°

m∠B + m∠D = 180°.

Since

m∠A = x + 16,
m∠B = x,
m∠C = 6x - 4,
m∠D = 2x + 16

we can use either pair of angle measures to work out the value of x and then find the value of each angle.

We can verify the first option is the only correct one.

m∠A + m∠C = 180°
(x + 16) + (6x − 4) = 180

3 0

3 years ago