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3 years ago

I will give out BRAINLYIST if u can answer this. qwertrewertyuiuytrfghsj

Mathematics

2 answers:

deff fn [24]3 years ago

7 0

Savsvwvsgsvajsmqkabadacags s

Step-by-step explanation:

Hope this helped

faltersainse [42]3 years ago

4 0

Answer:

I think it is

Step-by-step explanation:

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How to solve inequalities

Ulleksa [173]

Answer:

Step 1 Eliminate fractions by multiplying all terms by the least common denominator of all fractions.

Step 2 Simplify by combining like terms on each side of the inequality.

Step 3 Add or subtract quantities to obtain the unknown on one side and the numbers on the other.

Step 4 Divide each term of the inequality by the coefficient of the unknown. If the coefficient is positive, the inequality will remain the same. If the coefficient is negative, the inequality will be reversed.

Step 5 Check your answer.

3 0

3 years ago

Read 2 more answers

Solve and type in 'ab' 8×a=32,a+26=b+1,a<20<b

Whitepunk [10]

8*a=32
32:8=a
4=a

4+26=b

30=b

3 0

3 years ago

PLEASE HELP QUICK! I’ll give brainleist!!!

Fudgin [204]

1. set up the equation which makes these shapes equal, 1/2(2(x+1)) = 1x

2. solve, x+1=x, 1=0

3. since this is impossible, there is no solution and zero answers

5 0

3 years ago

What type of triangle has side lengths 9, 10, and √130? A. obtuse B. not a triangle C. acute D. right

EastWind [94]

Answer: Option C.

Step-by-step explanation:

The lengths of our triangle are:

9, 10 and √130.

If the triangle is a triangle rectangle, by the Pitagoream's theorem we have:

A^2 + B^2 = H^2

in this case H is the larger side, this must be √130.

then:

A and B must be 9 and 10.

9^2 + 10^2 = (√130)^2

81 + 100 = 130

This is false, so this is NOT a triangle rectangle, the hypotenuse is shorter than it should be.

Now, we have some kind of rule:

if A^2 + B^2 = H^2 then we have one angle of 90° and two smaller ones. (triangle rectangle)

if A^2 + B^2 > H^2 then all the angles are smaller than 90°, this is an acute triangle.

if A^2 + B^2 < H^2 then we have one angle larger than 90°, this is an obtuse angle.

(H is always the larger side, A and B are the two shorter ones).

In this case:

81 + 100 > 130

Then this must be an acute angle.

3 0

2 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

3 years ago