The value of K for which f(x) is a valid probability density function is 1/4.
<h3>How to solve for the value of K</h3>
![K[\frac{2^2}{2} -0]+[K[4(4-2)-(\frac{4^2}{2} -\frac{2^2}{2} )]=1](https://tex.z-dn.net/?f=K%5B%5Cfrac%7B2%5E2%7D%7B2%7D%20-0%5D%2B%5BK%5B4%284-2%29-%28%5Cfrac%7B4%5E2%7D%7B2%7D%20-%5Cfrac%7B2%5E2%7D%7B2%7D%20%29%5D%3D1)
open the equation
![K\frac{4}{2}+K[8 - (\frac{16}{2} -\frac{4}{2} )] = 1\\](https://tex.z-dn.net/?f=K%5Cfrac%7B4%7D%7B2%7D%2BK%5B8%20-%20%28%5Cfrac%7B16%7D%7B2%7D%20%20-%5Cfrac%7B4%7D%7B2%7D%20%29%5D%20%3D%201%5C%5C)
![2K+K[\frac{4}{2} ]=1](https://tex.z-dn.net/?f=2K%2BK%5B%5Cfrac%7B4%7D%7B2%7D%20%5D%3D1)
2K + 2K = 1
4K = 1
divide through by 4
K = 1/4
Read more on probability density function here
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Answer:
slope of M'N' = 1
Explanation:
First, we will need to get the coordinates of points M' and N':
We are given that the dilation factor (k) is 0.8
Therefore:
For point M':
x coordinate of M' = k * x coordinate of M
x coordinate of M' = 0.8 * 2 = 1.6
y coordinate of M' = k * y coordinate of M
y coordinate of M' = 0.8 * 4 = 3.2
Therefore, coordinates of M' are (1.6 , 3.2)
For point N':
x coordinate of N' = k * x coordinate of N
x coordinate of N' = 0.8 * 3 = 2.4
y coordinate of N' = k * y coordinate of N
y coordinate of N' = 0.8 * 5 = 4
Therefore, coordinates of M' are (2.4 , 4)
Then, we can get the slope of M'N':
slope = (y2-y1) / (x2-x1)
For M'N':
slope = (3.2-4) / (1.6-2.4)
slope = 1
Hope this helps :)
I believe the answer would be 6.3 feet if you use Pythagorean theorem
Answer:
The mean depends on the no. of family members but the question hasn't mentioned it. So I have no idea what to do with this.
