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anygoal [31]
3 years ago
8

A boat is being towed such that the tow line is at an angle of 30° with respect to the surface of the ocean. If the boat is towe

d with a force of 50 Newtons for 7,000 meters, approximately how much work is done?
A. 152,000 Joules
B. 175,000 Joules
C. 303,000 Joules
D. 350,000 Joules

Mathematics
2 answers:
marin [14]3 years ago
8 0

Answer:

C: 303,000 Joules

Step-by-step explanation:

Edge 2020

pentagon [3]3 years ago
5 0

Answer:

C. 303,000 Joules

Step-by-step explanation:

1. use abcos(theta)

a=50

b=7000

theta=30 degrees

2. (50)(7000)cos(30)=303,000

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XClusive! Why or why not?
Furkat [3]

wearing because of the division of running man.

Step-by-step explanation:

The statistics are divided by 29 to get the answer in cubic cm.

6 0
2 years ago
Write an equation in slope-intercept form of the line having the given slope and y-intercept.
pychu [463]

Answer:

The answer to your question is   y = 4/6x - 4

Step-by-step explanation:

Data

m = 4/6

P (0, -4)

slope-intercept form = ?      y = mx + b    where m is the slope and

                                                                  b is the y-intercept

Formula

           y - y1 = m(x - x1)

Substitution

           y - (-4) = 4/6(x - 0)

Simplification

           y + 4 = 4/6x

Result

                 y = 4/6x - 4

slope = 4/6  y-intercept = -4

7 0
3 years ago
What is the estimate of -4.2 - (-2.9). Show your work
irakobra [83]

Answer:

-1

Step-by-step explanation:

-4.2-(-2.9)

-4.2➡ is about -4

-2.9➡is about -3

-4-(-3)

-4+3

-1

5 0
3 years ago
Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u > 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
3 years ago
Is w^2-9w+81 a trinomial square
Yuri [45]
No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
( \sqrt{a}x+ \sqrt{c})^{2} or ( \sqrt{a}x- \sqrt{c})^{2}
so
if w^2-9w+81 is perfect square, factored form is either
( \sqrt{1}x+ \sqrt{81})^{2} or ( \sqrt{1}x- \sqrt{81})^{2}  aka ( x+9)^{2} or  ( x-9)^{2}
expand them
(x+9)^2=x^2+18x+81, wron middle term

(x-9)^2=x^2-18x+81 wrong

so it is not






8 0
3 years ago
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