A boat is being towed such that the tow line is at an angle of 30° with respect to the surface of the ocean. If the boat is towe
d with a force of 50 Newtons for 7,000 meters, approximately how much work is done?
A. 152,000 Joules
B. 175,000 Joules
C. 303,000 Joules
D. 350,000 Joules
A. 152,000 Joules
B. 175,000 Joules
C. 303,000 Joules
D. 350,000 Joules
2 answers:
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The raised vegetable garden in Susan's yard is in the shape of a rectangular prism with a volume of 48 cubic feet and a height of 3/4 foot. <span>The base of the rectangular prism is not a square and the width is greater than 2 feet. What is the length and width of the rectangular prism?
let
x-------> the length of the base of the rectangular prism
</span>y-------> the width of the base of the rectangular prism
<span>
we know that
volume of the prism=area of the base*height
volume=48 ft</span>³
<span>height of the prism=3/4 ft
area of the base=volume/height--------> 48/(3/4)---> 48*4/3----> 64 ft</span>²
<span>
area of the base=64 ft</span>²
<span>area of the base=x*y
64=x*y--------> equation 1
y=x+2--------> equation 2
substitute equation 2 in equation 1
64=x*[x+2]-----> 64=x</span>²+2x------> x²+2x-64=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=7.062 ft
y=x+2-----> y=7.062+2-----> y=9.062 ft
the answer is
</span>the length of the base of the rectangular prism is 7.062 ft
the width of the base of the rectangular prism is 9.062 ft<span>
</span>
The raised vegetable garden in Susan's yard is in the shape of a rectangular prism with a volume of 48 cubic feet and a height of 3/4 foot. <span>The base of the rectangular prism is not a square and the width is greater than 2 feet. What is the length and width of the rectangular prism?
let
x-------> the length of the base of the rectangular prism
</span>y-------> the width of the base of the rectangular prism
<span>
we know that
volume of the prism=area of the base*height
volume=48 ft</span>³
<span>height of the prism=3/4 ft
area of the base=volume/height--------> 48/(3/4)---> 48*4/3----> 64 ft</span>²
<span>
area of the base=64 ft</span>²
<span>area of the base=x*y
64=x*y--------> equation 1
y=x+2--------> equation 2
substitute equation 2 in equation 1
64=x*[x+2]-----> 64=x</span>²+2x------> x²+2x-64=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=7.062 ft
y=x+2-----> y=7.062+2-----> y=9.062 ft
the answer is
</span>the length of the base of the rectangular prism is 7.062 ft
the width of the base of the rectangular prism is 9.062 ft<span>
</span>
Answer:
<u>Step-by-step explanation:</u>