Use synthetic division 6. (3x2 – 13x – 10) ÷ (x + 5)
1 answer:
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Answer:
option 1) 50
Step-by-step explanation:
Let m and w denote the men and women respectively.
From the question, if the groom invited w number of women, then bride invited 2w number of women.
Also, if the bride invited m number of men,then the groom invited 2m.
Hence we can write the following maths equation:
w+2m=105.........1
2w+m=135.........2
We multiply eqn(1) by 2 to get eqn(3)
This implies that,
2w+4m=210.......3
We then subtract eqn (2) from eqn(3) to obtain;
3m=75
we divide through by 3
Substituting the value of m into eqn (1)
to find the value for w
subtracting 50 from both sides.
So we can say the :
bride invited 25 men and 110 women,
groom invited 50 men and 55 women.