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icang [17]
3 years ago
10

Tina is fixing to get rectangular signs he wants to space metal trim around the side and just the rectangle measures 32 inches b

y 9 inches how much trim will Tina need
Mathematics
1 answer:
Goshia [24]3 years ago
3 0
You do 32+9=41 times 2 and you get 82 inches.
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Donut star bucks and donald duck
8 0
3 years ago
An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours
Firdavs [7]

Answer

Find out the  which system of equations could be used to determine the number of hours charged at the day rate (d) and at the night rate (n) .

To proof

As given in the question

Let us assume that the number of hours charged at the day rate = d

Let us assume that the number of hours charged at the night rate = n

An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours of use.

Total working hour in a company including day and night be  12 hours .

than the equation become in the form

d + n = 12

also

An online data base charges $25 an hour during the day

$12.50 an hour at night.

If a research company paid $250 for 12 hours of use.

than the equation becomes

25d + 12.50n = 250

than the two equation are

d + n = 12 , 25d + 12.50n = 250

multiply first by 25 and subtracted  from 25d + 12.50n = 250

25d - 25d + 12.50n - 25n = 250 - 300

12.5 n = 50

n = \frac{50}{12.5}

n = 4hours

put this in the d + n = 12

d + 4 =12

d = 12-4

d = 8 hours

Therefore the number of hours charged at the day rate  is 8 hours  and at the night rate is  4hours .

Hence proved



4 0
3 years ago
4)In order to set rates, an insurance company is trying to estimate the number of sick daysthat full time workers at an auto rep
bagirrra123 [75]

Answer:

A sample of 18 is required.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.92}{2} = 0.04

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.04 = 0.96, so Z = 1.88.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the standard deviation was 2.2 days.

This means that \sigma = 2.2

How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

M = z\frac{\sigma}{\sqrt{n}}

1 = 1.88\frac{2.2}{\sqrt{n}}

\sqrt{n} = 1.88*2.2

(\sqrt{n})^2 = (1.88*2.2)^2

n = 17.1

Rounding up:

A sample of 18 is required.

3 0
3 years ago
A bag contains 6 blue counters and 4 red counters. I take two counters out at random. My
Step2247 [10]

Answer:

Possible outcome=6+4=10

P(red counter)=2/10=1/5

6 0
3 years ago
Pamela's boss rewards her hard work by telling her she is receiving a 12% raise. Pamela had been earning $15 per hour. After the
Maksim231197 [3]
It should be 16.8,
15 x (100% + 12%)
4 0
2 years ago
Read 2 more answers
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