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3 years ago

If line segment AB represents 25% what is the length of a line segment that is 100%

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

5 0

Answer:

AB*4

Step-by-step explanation:

25% of something is 1/4 of something. So, to get 100%, you have to multiply the length of AB times 4, and whatever answer you get is 100%.

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A motorcycle weighs 500 pounds. How many tons does the motorcycle weigh?

nexus9112 [7]

Answer:0.25 tons

Step-by-step explanation:

I looked it up on the internet

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3 years ago

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The measure of an angle is 164°. What is the measure of its supplementary angle?

storchak [24]

Answer:

Step-by-step explanation:

180-164=16 do the answer is 16

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2 years ago

Factor 8a^2+8ab+8ac+3a+3b+3c

nalin [4]

Answer:

(8a + 3)(a + b + c)

Step-by-step explanation:

8a^2 + 8ab + 8ac + 3a + 3b + 3c =

= 8a(a + b + c) + 3(a + b + c)

= (8a + 3)(a + b + c)

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3 years ago

Let f be the function given by f(x)= (x-1)(x^2-4)/x^2-a. For what positive values of a is f continuous for all real numbers x?

9966 [12]

Answer:

a =1 and a=4.

Step-by-step explanation:

The function is

$f(x)=\frac{(x-1)(x^2-4)}{x^2-a}$

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.

Now, for a a positive real we have that $x=\sqrt{a}$ will annulate the denominator, i.e

$(\sqrt{a})^2-a = a-a = 0$ . But, if a = 1 we have:

$f(x)=\frac{(x-1)(x^2-4)}{x^2-1} = \frac{(x-1)(x^2-4)}{(x-1)(x+1)}=\frac{(x^2-4)}{x+1}$

so, the value $x=\sqrt{a} = \sqrt{1} = 1$ won't annulate the denominator.

Now, for a = 4 we have:

$f(x)=\frac{(x-1)(x^2-4)}{x^2-4} = x-1$

so, the value $x=\sqrt{a} = \sqrt{4} = 2$ won't annulate the denominator.

In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.

4 0

3 years ago

Uma rede de supermercados fornece a seus clientes um cartão de crédito cuja identificação é formada por 3 letras distintas (dent

Vitek1552 [10]

Answer:

The correct option is (A) 33,600.

Step-by-step explanation:

The question is:

A supermarket chain provides its customers with a credit card whose identification is formed by 3 different letters (among 26), followed by 4 different digits. A given city will receive cards with L as the third letter, the last number is zero and the penultimate is 1. The total number of distinct cards offered by such supermarket chain for that city is A) 33600 B) 37800 C) 43200 D ) 58500 E) 67600

Solution:

The general format of the credit cards provided by a supermarket chain is as follows:

X X X # # # #

Here, X represents letters and # represents numbers.

All the three letters have to different and all the four numbers have to different, i.e. no repetition allowed.

It is provided that a given city will receive cards with L as the third letter, the last number is zero and the penultimate is 1.

Then the general format of this cities credit cards is as follows:

X X L # # 1 0

Now there are two spaces left for letters and 2 for numbers.

As there are no repetition allowed the two letter spaces can be filled by:

Number of ways to select 2 letters = 25 × 24 = 600

And the number of ways to select two numbers when there is no repetition allowed is:

Number of ways to select 2 numbers = 8 × 7 = 56

Compute the total number credit cards available at the supermarket as follows:

Total number credit cards = 600 × 56 = 33600

Thus, the total number of distinct cards offered by such supermarket chain for that city is 33,600.

The correct option is (A).

3 0

3 years ago