Answer:
Step-by-step explanation:
Future amount = 100(1+0.70)³
= 100 × 1.70³
= 491.3
491 bacteria
Answer:
4.89 hours or you can round it to make 4.8 or 5 hours
Step-by-step explanation:
22/4.5=4.888...
Answer:
(1) ΔMAN ≅ ΔBOY
(2) ΔMAT ≅ ΔRUG
(3) ΔEBN ≅ ΔUHR
(4) ΔTOP ≅ ΔLID
(5) ΔCAT ≅ ΔDOG
(6) ΔITP ≅ ΔLOH
Step-by-step explanation:
The following combinations of the congruent triangle facts will be sufficient to prove triangles congruent.
The combinations are:
(1) SSS (side-side-side) : If three sides of a triangle are congruent to three sides of another triangle then the triangles are congruent.
(2) SAS (side-angle-side) : If two sides and included angle of a triangle are congruent to another triangle then the triangles are congruent.
(3) ASA (angle-side-angle) : If two angles and included side of a triangle are congruent to another triangle then the triangles are congruent.
(4) RHS (right angle-hypotenuse-side) : If the hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle, the right triangles are congruent.
Part (1):
As we are given two triangles.
Side AM = Side OB
Side MN = Side BY
Side AN = Side OY
That means,
ΔMAN ≅ ΔBOY
Part (2):
As we are given two triangles.
Side MA = Side RU
Side MT = Side RG
Side AT = Side UG
That means,
ΔMAT ≅ ΔRUG
Part (3):
As we are given two triangles.
Side EB = Side UH
Side BN = Side HR
Side NE = Side RU
That means,
ΔEBN ≅ ΔUHR
Part (4):
As we are given two triangles.
Side OT = Side IL
Side OP = Side ID
Side PT = Side DL
That means,
ΔTOP ≅ ΔLID
Part (5):
As we are given two triangles.
Side AC = Side OD
Side AT = Side OG
Side TC = Side GD
That means,
ΔCAT ≅ ΔDOG
Part (6):
As we are given two triangles.
Side TP = Side OH
Side IT = Side LO
Side IP = Side LH
That means,
ΔITP ≅ ΔLOH
Let be x the number that Ben thought of, and write the equation:
x/2 + x/4 = 60
Solve for x:
3x/4 = 60
3x = 60*4
x = 240/3
x = 80
Ben thought 80.
To verify this, we can simply find the area of the triangle using the well-known formula
, where
and
are the base and height, respectively of the triangular region
. We have
, so the area is
, as expected.