We know that
[perimeter of rectangle]=2*(<span>length+width)
</span>
Let
x-----------> length
y-----------> width
so
P=2*(x+y)-----------> 244=2*(x+y)-----> x+y=122-------> y=122-x
Area=x*y-------> x*(122-x)----> 122x-x²
find the derivative function and equals to zero
122-2x=0-----> 122=2x----------> x=61 m
y=122-x------> y=122-61---------> y=61 m
<span>the maximum area is given by a square
</span>
the answer is
is a square of side 61 m
Answer: The answer is A. -21
Its simplified and i just multiplied 3 by -7 :)
Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
The solution to the problem is as follows:
<span>7(4)/4(4) = 28/16
28+16= 44
</span>
Therefore, the size of the graduating class would be 44 students in all.
I hope my answer has come to your help. God bless and have a nice day ahead!