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Answer:
![Mean = 100](https://tex.z-dn.net/?f=Mean%20%3D%20100)
![Median = 96](https://tex.z-dn.net/?f=Median%20%3D%2096)
Step-by-step explanation:
Given
--- coefficient of variation
![mode = 88](https://tex.z-dn.net/?f=mode%20%3D%2088)
![Skp = 0.4](https://tex.z-dn.net/?f=Skp%20%3D%200.4)
Required
The mean and the median
The coefficient of variation is calculated using:
![C_v = \frac{\sigma}{\mu}](https://tex.z-dn.net/?f=C_v%20%3D%20%5Cfrac%7B%5Csigma%7D%7B%5Cmu%7D)
Where:
mean
So:
![30\% = \frac{\sigma}{\mu}](https://tex.z-dn.net/?f=30%5C%25%20%3D%20%5Cfrac%7B%5Csigma%7D%7B%5Cmu%7D)
Express percentage as decimal
![0.30 = \frac{\sigma}{\mu}](https://tex.z-dn.net/?f=0.30%20%3D%20%5Cfrac%7B%5Csigma%7D%7B%5Cmu%7D)
Make
the subject
![\sigma = 0.30\mu](https://tex.z-dn.net/?f=%5Csigma%20%3D%200.30%5Cmu)
The coefficient of skewness is calculated using:
![Skp = \frac{\mu - Mode}{\sigma}](https://tex.z-dn.net/?f=Skp%20%3D%20%5Cfrac%7B%5Cmu%20-%20Mode%7D%7B%5Csigma%7D)
This gives:
![0.4 = \frac{\mu - 88}{\sigma}](https://tex.z-dn.net/?f=0.4%20%3D%20%5Cfrac%7B%5Cmu%20-%2088%7D%7B%5Csigma%7D)
Make
the subject
![\sigma = \frac{\mu - 88}{0.4 }](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cfrac%7B%5Cmu%20-%2088%7D%7B0.4%20%7D)
Equate both expressions for
![0.30\mu = \frac{\mu - 88}{0.4 }](https://tex.z-dn.net/?f=0.30%5Cmu%20%3D%20%5Cfrac%7B%5Cmu%20-%2088%7D%7B0.4%20%7D)
Cross multiply
![0.4*0.30\mu = \mu - 88](https://tex.z-dn.net/?f=0.4%2A0.30%5Cmu%20%3D%20%5Cmu%20-%2088)
![0.12\mu = \mu - 88](https://tex.z-dn.net/?f=0.12%5Cmu%20%3D%20%5Cmu%20-%2088)
Collect like terms
![0.12\mu - \mu = - 88](https://tex.z-dn.net/?f=0.12%5Cmu%20-%20%5Cmu%20%3D%20%20-%2088)
![-0.88\mu = - 88](https://tex.z-dn.net/?f=-0.88%5Cmu%20%3D%20%20-%2088)
Divide both sides by -0.88
![\mu = 100](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%20100)
Hence:
![Mean = 100](https://tex.z-dn.net/?f=Mean%20%3D%20100)
Calculate
![\sigma = 0.30\mu](https://tex.z-dn.net/?f=%5Csigma%20%3D%200.30%5Cmu)
![\sigma = 0.30 * 100](https://tex.z-dn.net/?f=%5Csigma%20%3D%200.30%20%2A%20100)
![\sigma = 30](https://tex.z-dn.net/?f=%5Csigma%20%3D%2030)
So:
Also, the coefficient of skewness is calculated using:
![Skp = \frac{3 * (Mean - Median)}{\sigma}](https://tex.z-dn.net/?f=Skp%20%3D%20%5Cfrac%7B3%20%2A%20%28Mean%20-%20Median%29%7D%7B%5Csigma%7D)
![0.4= \frac{3 * (100 - Median)}{30}](https://tex.z-dn.net/?f=0.4%3D%20%5Cfrac%7B3%20%2A%20%28100%20-%20Median%29%7D%7B30%7D)
Multiply both sides by 30
![0.4*30= 3 * (100 - Median)](https://tex.z-dn.net/?f=0.4%2A30%3D%203%20%2A%20%28100%20-%20Median%29)
Divide both sides by 3
![0.4*10= 100 - Median](https://tex.z-dn.net/?f=0.4%2A10%3D%20100%20-%20Median)
![4= 100 - Median](https://tex.z-dn.net/?f=4%3D%20100%20-%20Median)
Collect like terms
![Median = 100 - 4](https://tex.z-dn.net/?f=Median%20%3D%20100%20-%204)
![Median = 96](https://tex.z-dn.net/?f=Median%20%3D%2096)
Correlation coefficients whose magnitude are between 0.3 and 0.5 indicate variables which have a low correlation.<span> Correlation coefficients whose magnitude are less than 0.3 have little if any (linear) correlation.</span>
Answer:
Step-by-step explanation:
h(x) = 36 - 4.9x^3
Let x be 1.3
The question is not entirely clear. Looks like the iphone moved. Not only that, but the question is not really clear either. I'm taking it to mean that h is the distance from the GROUND to the ROCK after 1.3 seconds.
h(x) = 36 - 4.9(1.3)^2
h(1.3) = 36 - 4.9 * 1.3 * 1.3
h(1.3) = 36 - 27.719
h(1.3) = 8.28 m
I can help but you just need to post the questions