Hi there!
Let x=1
X-3y=6
1-3y=6
-3y=6-1
-3y=5
Y=-5/3
Therefore a point would be (1, -5/3)
Hope this helps!
Answer:
Interquartile range = 24
Step-by-step explanation:
First we need to put the sequence in order from lowest to highest.
0, 1, 3, 5, 21, 25, 45
5 is the median and then from 5 to 0 we need to find the lowest interquartile in between it which is 1.
Highest interquartile from 5 to 45 finding the middle will be 25.
Interquartile range = highest interquartile - lowest quartile
25-1 = 24
Yes,the answer is 3/4 when simplified
