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4 years ago

What is the IQR (Inter Quartile Range 0, 21, 45, 3, 1, 5, 25

Mathematics

1 answer:

patriot [66]4 years ago

4 0

Answer:

Interquartile range = 24

Step-by-step explanation:

First we need to put the sequence in order from lowest to highest.

0, 1, 3, 5, 21, 25, 45

5 is the median and then from 5 to 0 we need to find the lowest interquartile in between it which is 1.

Highest interquartile from 5 to 45 finding the middle will be 25.

Interquartile range = highest interquartile - lowest quartile

25-1 = 24

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3 years ago

Segment BD is an altitude of triangle ABC. Find the area of the triangle.

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Answer: The correct option is A, i.e., 7.5.

Explanation:

It is given that ABC is a triangle and BD is an altitude.

Since BD is an altitude, therefore the height of the triangle is BD and the base of the triangle is AC.

The distance formula to find the distance between two points is,

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

First, we find BD, where B(-1,4) and D(2,4).

$BD=\sqrt{(2+1)^2+(4-4)^2}=\sqrt{9} =3$

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So, the base of the triangle is 5.

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$A=\frac{1}{2}\times {\text{base}}\times {\text{height}}$

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3 years ago

Read 2 more answers

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Answer:

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