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Aleonysh [2.5K]
4 years ago
10

What is the IQR (Inter Quartile Range 0, 21, 45, 3, 1, 5, 25

Mathematics
1 answer:
patriot [66]4 years ago
4 0

Answer:

Interquartile range = 24

Step-by-step explanation:

First we need to put the sequence in order from lowest to highest.

0, 1, 3, 5, 21, 25, 45

5 is the median and then from 5 to 0 we need to find the lowest interquartile in between it which is 1.

Highest interquartile from 5 to 45 finding the middle will be 25.

Interquartile range = highest interquartile - lowest quartile

25-1 = 24

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The movie ended at 7:15 p.m. and lasted 2 hours 40 minutes. What time did the movie begin?
nekit [7.7K]

Answer:

The movie started in 4:35 pm

Step-by-step explanation:

the easy way to do this

Step one: subtract 2 hours from 7:15 pm which is 5:15 pm

step two: to subtract 30 min from 5:15 which is 4:45 pm

step three: to subtract 10 min from 4:45 pm which is 4:35 pm

<h3>∴ The movie started in 4:35 pm</h3>
8 0
3 years ago
Read 2 more answers
HI MATHS EXPERTS PLS ANSWER ASAP PLS I AM DESPERATE
katovenus [111]

c. 2310 (1st pic)

circumference of circle = 2πr

44= 2 × 22/7 r

44 × 7 / (2 × 22) = r

7 = r

volume of cylinder = πr^2h

= 22/7 × (7)^2 ×15

= 2310

b. -2/x+3 (2nd pic)

(work attached)

a. 80° (3rd pic)

Total number of degrees is 180

180-(60+40)=80

c. 9 (5th pic)

(27^1/3)^2

3^2

=9

sorry i couldn't solve the 4th pic but I hope this helps!

please mark me brainliest!

3 0
3 years ago
Sean, Ryan, and Justin shared a sum of money in the ratio 3 : 4 : 5. If Sean received $30, what was the sum of money shared?
Solnce55 [7]
In order to solve this problem, you need to find out how 3 of something  is 30
In this case, you multiply 10.
Sean= 3×10=30
Ryan= 4×10=40
Justin=  5×10= 50
30+40+50= 120
The answer is $120
Hope this helps
7 0
3 years ago
If there’s 30 candies in 1.5 ounce bag how many candies are in a 4.2 ounce bag
mezya [45]

Answer:

84 candies in a 4.2 ounce bag

Step-by-step explanation:

30/1.5 = 20 candies per ounce

20(4.2) = 84 candies in a 4.2 ounce bag

8 0
3 years ago
The length of a rectangle is six times its width. if the area of the rectangle is 216 ft2 , find its perimeter.
uysha [10]
L = 6w
A = 216
A = lw
216 = (6w)(w)
216 = 6w^2
216/6 = w^2
36 = w^2
w = 6
l = 6(6)
l = 36
P = 2l + 2w
P = 2(36) + 2(6)
P = 72 + 12
P=84
7 0
3 years ago
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