Vertex form formula: y = a(x-h)^2 +k, with vertex (h,k)
There are multiple ways to find the vertex. One way is to find the roots and then find the x value exactly in between them, because this parabola is symmetrical.
0 = (x - 3)(x + 2), so x = 3 and -2. The point directly in the middle is x = 1/2 = h
To find the y value of the vertex, plug in 1/2 to the equation.
(1/2)^2 - 2(1/2) + 5 = 4.25 = k
y = (x - 0.5)^2 + 4.25
Looks like you didn't finish because there is no question. I'll break that problem down for you and hopefully the missing question will be answered. :)
$11 x 40h = $440
Overtime pay and holiday pay is time and a half = $11 x 1.5 = $16.50
$16.50 x 9 hours overtime = $148.50
$16.50 x 12 hours holiday = $198.00
Holiday and OT= $346.50
Total of check including regular hours, holiday pay and overtime = $786.50
Question 1:
Slope = 1/5
y = mx + c
y = 1/5 x + c
at point (5, -1)
-1 = 1/5 (5) + c
- 1= 1 + c
c = - 2
y = 1/5x - 2
5y = x - 10
Question 2:
slope = (9-5)/(3-1)
Slope = 2
y = mx + c
y = 2x + c
at point (1, 5)
5 = 2(1) + c
c = 5 - 2
c = 3
y = 2x + 3
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2x^2 + 14x + 12 = 0
x^2 + 7x + 6 = 0
( x + 1 )( x + 6 ) = 0 ==》 x = - 1 Or x = - 6
