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MariettaO [177]
3 years ago
11

Jillian is selling boxes of cookies to raise money for her basketball team. The 10 oz. box costs $3.50, while the 16 oz. box cos

ts $5.00. At the end of one week, she collected $97.50, selling a total of 24 boxes. The system of equations that models her sales is below. x y
Mathematics
1 answer:
RideAnS [48]3 years ago
8 0

Answer:

Jillian sold 15 ten-oz bags and 9 sixteen-oz bags.

Step-by-step explanation:

Let x represent number of 10-oz bags and y represent number of 16-oz bags.

We have been given that Jillian sold 24 boxes of cookies in total. We can represent this information in an equation as:

x+y=24...(1)

We are also told that 10 oz. box costs $3.50, while the 16 oz. box costs $5.00, so the cost of x 10-oz bags would be 3.50x and cost of y 16-oz bags would be 5y.

At the end of one week, she collected $97.50. We can represent this information in an equation as:

3.5x+5y=97.50...(2)

Now, we will use substitution method to solve our system of equations. From equation (1), we will get:

y=24-x

Substitute this value in equation (2):

3.5x+5(24-x)=97.50

3.5x+120-5x=97.50

-1.5x+120=97.50

-1.5x+120-120=97.50-120

-1.5x=-22.5

\frac{-1.5x}{-1.5}=\frac{-22.5}{-1.5}

x=15

Therefore, the number of 10-oz boxes sold be Jillian is 15.

Now, we will substitute x=15 in equation (1) to solve for y.

15+y=24

15-15+y=24-15

y=9

Therefore, the number of 16-oz boxes sold be Jillian is 9.

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It is the measure of distance between the two points and is known as length. The length is measured in meters generally.

Ed needed to extend the string on his kite. The current string was seven and three-fourths feet that is (7  3/4).

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2 years ago
Ellie want to buy new shoes that is in sale for $80. She saved $60. How much more money does she need
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$20

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3 years ago
Chelsea took out three loans for a total of ​$ 78 comma 000 78,000 to start an organic orchard. Her​ business-equipment loan was
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Answer:

Business-equipment loan, A=$15000

Small-business loan, B=$24000

home-equity loan, C= $39000

Step-by-step explanation:

Let the Business-equipment loan at an interest rate of​ 11%=A

Let the​ small-business loan was at an interest rate of 5​% =B

Let her​ home-equity loan was at an interest rate of 4.5​%.=C

Since her total Loan=$78000

A+B+C=78000....(I)

Simple Interest = (P X R X T)/100

Since the Time, T=1 year

Interest on A = 0.11A

Interest on B = 0.05B

Interest on C = 0.045C

The total simple interest due on the loans in one year was ​$4605.

0.11A+0.05B+0.045C=4605....(II)

The annual simple interest on the​ home-equity loan was ​$105 more than the interest on the​ business-equipment loan.

0.045C = 0.11A +105...(III)

We proceed to solve the simultaneous equations.

A+B+C=78000....(I)

0.11A+0.05B+0.045C=4605....(II)

0.045C = 0.11A +105...(III)

From (III), 0.045C = 0.11A +105

Substitute 0.045C = 0.11A +105 into (II).

0.11A+0.05B+0.11A +105=4605

0.22A+0.05B=4500

From (III),

C=\frac{22A}{9}+\frac{7000}{3}

Substitute into (I)

A+B+\frac{22A}{9}+\frac{7000}{3}=78000

\frac{31A}{9}+B=78000-\frac{7000}{3}

\frac{31A}{9}+B=\frac{227000}{3}

\frac{31A+9B}{9}=\frac{227000}{3}

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From (III)

C=\frac{22A}{9}+\frac{7000}{3}

C=\frac{22X15000}{9}+\frac{7000}{3} =39000

C=$39000

from (I)

A+B+C=78000

15000+B+39000=78000

B=$24000

8 0
3 years ago
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