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CaHeK987 [17]
3 years ago
13

How to solve a quadratic equation when c=0

Mathematics
1 answer:
kherson [118]3 years ago
6 0
Lets say we have a quadratic equation:

3x^2 + x + 0 = 0

Now, since if we add or subtract 0 from something, the original value stays the same, which means we can write the equation as 3x^2 + x = 0 and ignore the “+0”.

In these kinds of equations, you /can/ use the quadratic formula, but theres a much quicker way. If we factor 3x^2 + x, we get x(3x + 1) = 0. Here, x has two possible values — since the result of the multiplication is 0, that means that either one expression or the other must equal 0. In essence:

If x(3x+1) = 0 then x = 0 or 3x+1 = 0
One of the solutions is that x = 0. Lets find the other.

3x+1=0
3x= -1
x = -1/3

So x1 = 0 and x2 = -1/3. So basically you solve these equations using basic factorization. :)
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Evaluate 48/6-10/3 please and thank you :)))
vodomira [7]

Answer:

14/3

Step-by-step explanation:

Simplify the following:

48/6 - 10/3

Hint: | Reduce 48/6 to lowest terms. Start by finding the GCD of 48 and 6.

The gcd of 48 and 6 is 6, so 48/6 = (6×8)/(6×1) = 6/6×8 = 8:

8 - 10/3

Hint: | Put the fractions in 8 - 10/3 over a common denominator.

Put 8 - 10/3 over the common denominator 3. 8 - 10/3 = (3×8)/3 - 10/3:

(3×8)/3 - 10/3

Hint: | Multiply 3 and 8 together.

3×8 = 24:

24/3 - 10/3

Hint: | Subtract the fractions over a common denominator to a single fraction.

24/3 - 10/3 = (24 - 10)/3:

(24 - 10)/3

Hint: | Subtract 10 from 24.

| 2 | 4

- | 1 | 0

| 1 | 4:

Answer:  14/3

5 0
4 years ago
13. Find the exact value of sin 30 ° - sin 45 ° cos 45 ° .<br> a. 0 <br> b. 1/2 <br> c. 1 <br> d. 2
Marianna [84]
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4 years ago
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Answer:

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Step-by-step explanation:

In three months if the glacier retreated 9.36 then you can find what it retreaded in one month by division so,

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Area of a rectangle 2 is more by 0.88 inche^2
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Answer:

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Step-by-step explanation:

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