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3 years ago

Evaluate 48/6-10/3 please and thank you :)))

Mathematics

1 answer:

vodomira [7]3 years ago

5 0

Answer:

14/3

Step-by-step explanation:

Simplify the following:

48/6 - 10/3

Hint: | Reduce 48/6 to lowest terms. Start by finding the GCD of 48 and 6.

The gcd of 48 and 6 is 6, so 48/6 = (6×8)/(6×1) = 6/6×8 = 8:

8 - 10/3

Hint: | Put the fractions in 8 - 10/3 over a common denominator.

Put 8 - 10/3 over the common denominator 3. 8 - 10/3 = (3×8)/3 - 10/3:

(3×8)/3 - 10/3

Hint: | Multiply 3 and 8 together.

3×8 = 24:

24/3 - 10/3

Hint: | Subtract the fractions over a common denominator to a single fraction.

24/3 - 10/3 = (24 - 10)/3:

(24 - 10)/3

Hint: | Subtract 10 from 24.

| 2 | 4

- | 1 | 0

| 1 | 4:

Answer: 14/3

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I cant believe how bad my brother, Reuben, is at growing things. He bought a whole bunch of plants at the nursery the other day.

jeka94

Answer:

68 plants.

Step-by-step explanation:

Let x represent the number of plants that Reuben bought from the nursery.

We have been given that Reuben bought a whole bunch of plants at the nursery the other day. Right away, five died. So number of plant left would be $x-5$ .

We are also told that then our dog dug up 2/9 of them. So number of plants left after dug-up would be $\frac{2}{9}(x-5)$ .

Further a rabbit came and ate ½ of what was left. So number of plants left would be $\frac{\frac{2}{9}(x-5)}{2}=\frac{2}{9\times 2}(x-5)=\frac{1}{9}(x-5)$ .

Since Reuben had only 7 plants left, so we will equate our expression with 7 and solve for x as:

$\frac{1}{9}(x-5)=7$

$9\times \frac{1}{9}(x-5)=7\times 9$

$x-5=63$

$x-5+5=63+5$

$x=68$

Therefore, Reuben bought 68 plants at the nursery.

6 0

3 years ago

the length of a rectangle is 8cm more than the width and its area is 172cm2 .find the width of the rectabgle

nikdorinn [45]

$l-the\ length\\l+8-the\ width\\A=172\ cm^2\\\\A=lengtf\cdot width\\\\subtitute\\\\l(l+8)=172\\\\l^2+8l=172\ \ \ |subtract\ 172\ from\ both\ sides\\\\l^2+8l-172=0\\a=1;\ b=8;\ c=-172\\\\\Delta=b^2-4ac\\\\\Delta=8^2-4\cdot1\cdot(-172)=64+688=752 > 0\\\\l_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ l_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{752}=\sqrt{16\cdot47}=4\sqrt{47}\\\\l_1=\dfrac{-8-4\sqrt{47}}{2\cdot1}=-4-2\sqrt{47} < 0\\\\l_2=\dfrac{-8+4\sqrt{47}}{2\cdot1}=-4+2\sqrt{47} > 0\\\\The\ width:l+8=-4+2\sqrt{47}+8=4+2\sqrt{47}\\\\Answer:\boxed{length=(2\sqrt{47}-4)cm;\ width=(4+2\sqrt{47})cm}$
$length\approx9.71cm;\ width\approx17.71cm$

4 0

3 years ago

(20 points!) Find the median, mode, range, Q1, Q2, Q3, IQR and outliers, if any, of the data set. Round to the nearest tenth of

shtirl [24]

Answer:

1:49

2:62

Step-by-step explanation:

it mightbe wrong idk

3 0

3 years ago

What is 1/4 + 12/20 written as an equivalent fraction ?