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3 years ago

6th Grade Math! Complete the function table and write the function rule. Please explain, since this is a written answer. Tysm!

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

4 0

Answer:

Its subtract 12.

Step-by-step explanation:

The first question mark is positive 6.

6-12= -6

The second question mark is -22.

Negative 10 minus 12 equals negative 22

Once you understand integers, it will be really easy. I was in 6th grade last year.

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The table below shows the ages of 50 people on a bus.

emmasim [6.3K]

Step-by-step explanation:

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2 years ago

Maria and Nate graphed lines on a coordinate plane. Maria's line is represented by the equation y = -5/6x +8. Nate's line is per

likoan [24]

Answer:

Option C: 6x-5y=15

Explanation:

y = -5/6x +8

8 is the y-intercept

-5/6x is the slope

when a slope is in fraction form the numerator is the y direction over the denominator how much the line changes in the x direction

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2 years ago

To make a specific orange color, a painter uses 14 of a can of red paint and 12 of a can of yellow paint. Fill in each statement

Otrada [13]

Answer: For every 1 can of red paint, the number of yellow paints used by the painter is $\frac{6}{7}$ and

There are approximately 29 cans of yellow paints for 34 cans of red paints.

Step-by-step explanation:

Since we have given that

Number of cans of red paint = 14

Number of cans of yellow paint = 12

According to question, we have to find that for every 1 can of red paint the painter uses what number of yellow paints;

Since the ratio of red paint to yellow paint is given by

$14:12\\\\7:6\\\\1:\frac{6}{7}$

So, for every 1 can of red paint, the number of yellow paints used by the painter is $\frac{6}{7}$

Similarly,

If Number of can of red paint is used = 34

So, Number of cans of yellow paint will be

$\frac{6}{7}\times 34\\\\=\frac{6\times 34}{7}\\\\=29\ approx.$

Hence, there are approximately 29 cans of yellow paints for 34 cans of red paints.

3 0

3 years ago

Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm

Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6, \sigma = 0.2$

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6-6}{0.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.

X = 6.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 5.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$