The answer is -2 (negative two) yards away from the goal line (meaning that the ball is in the end zone or past the goal line).
Answer:
6mph
Step-by-step explanation:
In this question, we are asked to calculate the speed at which Carol jogs, given that she has a particular speed when she jogs greater than when she walks.
Firstly, we should understand that she is taking the same distance, whether she jogs or walks.
Now, let’s say her jogging rate is x mph, this means that her walking rate would be (x - 4)mph. This is because her jogging rate is 4mph faster than her walking rate.
The total distance covered when jogging is thus 10/60 * x, while her total distance covered when walking would be 30/60 * (x-4)[we convert the time to hours]
We equate both since they are same distance:
x/6 = (x -4)/2
2x = 6(x - 4)
2x = 6x - 24
4x = 24
x = 6mph
Answer:
y = .75x - 4.5
Step-by-step explanation:
y = mx + b
m = slope ; b = y-int
slope = rise/ run = 3/4 = .75
y = .75x + b
Because it is hard to determine the exact y-intercept, we plug in a point (2,-3):
-3 = .75(2) + b
-3 = 1.5 + b
-4.5 = b -->
y = .75x - 4.5
The Solution:
Given:
Required:
Simplify the given expression.
Applying the rule of exponent, we get:
Answer:
1.6 -1.6 +1.6 is the following