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scoray [572]
3 years ago
14

A bag held 3 white marbles, 1 orange marble, and 2 green marbles. Anna drew a white marble and did not replace it. What is the p

robability of drawing a green marble next?
A. 1/6
B. 1/5
C. 1/3
D. 2/5
Mathematics
1 answer:
satela [25.4K]3 years ago
3 0
D because the total of marbles is 5 and the green marbles are 2
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Can you solve the equation?
Andreas93 [3]

Answer:

x=3 and 9

Step-by-step explanation:

; x-3=0

x=3 (change side change mark)

and

\frac{2}{3} x - 6 = 0

\frac{2}{3} x = 6

x = 6 \times  \frac{3}{2}

change side change mark.

So, x=9

If u wanna check the answer you can check by substitution x=3 and 9 in equation.

hope it helps you ☺️

3 0
3 years ago
Can someone plz help me with this equation this is hard
nikdorinn [45]

Answer:

5x - 4 = 11

Step-by-step explanation:

4 less than 5 times a number equals 11

5 times a number minus 4 equals 11

(5*x) - 4 = 11

I hope this helps!!!

5 0
3 years ago
Read 2 more answers
Abe made rectangular prism that is 48 cubic inches. what is 1 set of possible dimension for Abe's rectangular prism?
julsineya [31]
You just need three numbers that multiply to make 48. Because the volume of  a rectangular prism is abh.
1 1 48
2 1 24
3 1 16
4 1 12
6 1 8
2 3 8
2 2 12
2 4 6
3 4 4
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etc
5 0
3 years ago
Please help me on this problem
Anna71 [15]

Answer:

The pairs of integer having two real solution forax^{2} -6x+c = 0 are

  1. a = -4, c = 5
  2. a = 1, c = 6
  3. a = 2, c = 3
  4. a = 3, c = 3

Step-by-step explanation:

Given

ax^{2} -6x+c = 0

Now we will solve the equation by putting all the 6 pairs so we get the  following

-3x^{2} -6x-5 = 0 for a = -3 , c=-5

-4x^{2} -6x+5 = 0 for a = -4 , c=5

1x^{2} -6x+6 = 0 for a = 1 , c=6

2x^{2} -6x+3 = 0 for a = 2 , c=3

3x^{2} -6x+3 = 0 for a = 3 , c=3

5x^{2} -6x+4 = 0 for a = 5 , c=4

The above  all are Quadratic equations inn general form ax^{2} +bx+c=0

where we have a,b and c constant values

So for a real Solution we must have

Disciminant , b^{2} -4\timesa\timesc \geq 0

for a = -3 , c=-5 we have

Discriminant =-24 which is less than 0 ∴ not a real solution.

for a = -4 , c=5 we have

Discriminant = 116 which is greater than 0 ∴ a real solution.

for a = 1 , c=6 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 2 , c=3 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 3 , c=3 we have

Discriminant =0 which is equal to 0 ∴ a real solution.

for a = 5 , c=4 we have

Discriminant =-44 which is less than 0 ∴ not a real solution.

7 0
3 years ago
Can you write a ratio for one number in more than one way ?
notsponge [240]
Yes you can write a ratio in more than one way
7 0
3 years ago
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