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hodyreva [135]
3 years ago
5

If I invest $3600 at an interest rate of 4% per year, and contribute an additional $30 per month, how much will I have in 5 year

s?
Mathematics
1 answer:
SOVA2 [1]3 years ago
6 0
Http://www.pierce.ctc.edu/staff/dlippman/mathinsociety/Finance1.0.pdf I think this will help
You might be interested in
Find the values of λ for which the determinant is zero.
elena55 [62]

Answer:

Determinant are special number that can only be defined for square matrices.

Step-by-step explanation:

Determinant are particularly important for analysis. The inverse of a matrix exist, if the determinant is not equal to zero.

How to find determinant

For a 2×2 matrix

det ( \left[\begin{array}{cc}x&y\\a&z\end{array}\right] ) = xz-ay

For a 3×3 matrix

we first decompose it to 2×2

det (\left[\begin{array}{ccc}k&l&m\\o&p&q\\r&s&t\end{array}\right] )\\\\= k*det(\left[\begin{array}{cc}p&q\\s&t\end{array}\right] ) - l*det(\left[\begin{array}{cc}o&q\\r&t\end{array}\right] ) + m*det(\left[\begin{array}{cc}o&p\\r&s\end{array}\right] ) \\\\=k(pt-sq) - l(ot-rq) + m(os-rp)

Example

Find the values of λ for which the determinant is zero

\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right]

det(\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right])\\\\= s*det(\left[\begin{array}{cc}s&-1\\-1&1\end{array}\right] ) - (-1)*det(\left[\begin{array}{cc}-1&-1\\0&1\end{array}\right] ) + 0*det(\left[\begin{array}{cc}-1&s\\0&-1\end{array}\right] )\\\\= s(s(1)-(-1*-1)) - (-1)(-1*1 - (-1*0)) + 0\\= s(s - 1)) + 1(-1 + 0) \\=s^{2} -s-1

Equating the determinant to zero

s^{2} -s-1 =0\\

s = \frac{1}{2} * (1 ±5 )

s = 1.61 or -0.61

5 0
3 years ago
If a sequence is defined recursively by f(0) = 2 and
Tanzania [10]
If you would like to know how much is f(2), you can calculate this using the following steps:

f(0) = 2
f(n+1) = - 2 * f(n) + 3
f(1) = - 2 * f(0) + 3 = - 2 * 2 + 3 = - 4 + 3 = - 1
f(2) = - 2 * f(1) + 3 = - 2 * (-1) + 3 = 2 + 3 = 5

The correct result would be f(2) = 5.
5 0
3 years ago
Divide..................
Masja [62]

Answer:

option-A

Step-by-step explanation:

we are given

Dividend is

6x^2-19x+10

Divisor is

2x-5

we can use long division method

we get

Remainder is

=0

Quotient is

3x-2

so, we can write as

\frac{6x^2-19x+10}{2x-5}=3x-2+\frac{0}{2x-5}

\frac{6x^2-19x+10}{2x-5}=3x-2

6 0
2 years ago
Test in an hour. Please help.
ololo11 [35]
Now.. on the first one \bf \sqrt{-27}\cdot \sqrt{-3}\impliedby \textit{first, you convert them to "i" form}
\\\\\\
\sqrt{3^2\cdot 3\cdot -1}\cdot \sqrt{3\cdot -1}\implies \sqrt{3^2}\cdot \sqrt{3}\cdot \sqrt{-1}\cdot \sqrt{3}\cdot \sqrt{-1}
\\\\\\
3\sqrt{3}\ i\cdot \sqrt{3}\ i\implies 3(\sqrt{3})^2\ i^2\implies 3\cdot 3\cdot i^2\impliedby recall\quad i^2=-1
\\\\\\
-9\implies -9+0i
8 0
3 years ago
Help Meeeeeeeeeeeeeeeeeeeeeeee PLZZZ
OLEGan [10]

Answer:

3s(2000)

Step-by-step explanation:

I did it in my head lol

3 0
3 years ago
Read 2 more answers
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