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lubasha [3.4K]
3 years ago
13

According to the general equation for conditional probability, if P(A, B) =4/7

Mathematics
1 answer:
Neko [114]3 years ago
8 0

Answer:

P(A|B) = \frac{32}{49}

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(A|B) = \frac{P(A \cap B)}{P(B)}

In which

P(A|B) is the probability of event A happening, given that B happened.

P(A \cap B) is the probability of both A and B happening.

P(B) is the probability of B happening.

We have that:

P(A \cap B) = \frac{4}{7}, P(B) = \frac{7}{8}

So

P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{\frac{4}{7}}{\frac{7}{8}} = \frac{4}{7}*\frac{8}{7} = \frac{32}{49}

Then

P(A|B) = \frac{32}{49}

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