We have the following equation:
y = 2 (2.71) ^ x
It is an equation of the form:
y = A (b) ^ x
Where,
A: initial amount
b: growth rate
We have then that the initial amount occurs for x = 0
Substituting:
y = 2 (2.71) ^ 0
y = 2 (1)
y = 2
Answer:
the initial value of and in the equation y = 2 (2.71) ^ x is:
y = 2
Answer:
18
Step-by-step explanation:
When x equals -3, then the first equation is simplified to 9 + 6 + 3 = 18; and the second equation confirms the same answer by showing -6 x -3 = 18
Answer:
oh thats easy look so what you do is 500,000
13,000
1,000
200
90
Step-by-step explanation: 2
your welcome ^^
Answer:
Step-by-step explanation:
we know that
The quadratic equation 
is a vertical parabola
The axis of symmetry in a vertical parabola is a vertical line
The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex
The x-coordinate of the vertex is equal to the formula
therefore
the equation of the axis of symmetry is equal to
Assume P(xp,yp), A(xa,ya), etc.
We know that rotation rule of 90<span>° clockwise about the origin is
R_-90(x,y) -> (y,-x)
For example, rotating A about the origin 90</span><span>° clockwise is
(xa,ya) -> (ya, -xa)
or for a point at H(5,2), after rotation, H'(2,-5), etc.
To rotate about P, we need to translate the point to the origin, rotate, then translate back. The rule for translation is
T_(dx,dy) (x,y) -> (x+dx, y+dy)
So with the translation set at the coordinates of P, and combining the rotation with the translations, the complete rule is:
T_(xp,yp) R_(-90) T_(-xp,-yp) (x,y)
-> </span>T_(xp,yp) R_(-90) (x-xp, y-yp)
-> T_(xp,yp) (y-yp, -(x-xp))
-> (y-yp+xp, -x+xp+yp)
Example: rotate point A(7,3) about point P(4,2)
=> x=7, y=3, xp=4, yp=2
=> A'(3-2+4, -7+4+2) => A'(5,-1)
