Given a right angle triangle
The length of the legs are 4 and 7
we will find the hypotenuse using the Pythagorean theorem
So,
![\begin{gathered} h^2=7^2+4^2=49+16=65 \\ h=\sqrt[]{65}\approx8.062 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D7%5E2%2B4%5E2%3D49%2B16%3D65%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B65%7D%5Capprox8.062%20%5Cend%7Bgathered%7D)
Rounding to the nearest tenth
So, the answer is the length of the third side = 8.1
Answer: 16
Step-by-step explanation: When you have a set of parentheses in an order of operations problem, you must simplify what's inside that set of parentheses first before you do anything else.
So our first step here is to subtract 6 - 8 which gives us -2.
So in our next step we have 3 (-2)² + 8 ÷ 2.
Now remember to do exponents before you multiply.
So (-2)² is just -2 × -2 or 4.
So in our next step we have 3 x 4 + 8 ÷ 2.
Now, we multiply so we have 3 x 4 which is 12.
So we have 12 + 8 ÷ 2.
Now we can divide.
8 ÷ 2 is 4 so we have 12 + 4 or 16.
So the answer to this problem is 16.
Answer:
Around 30 times I believe
the answers that apply are B, D, and F
Quartic => polynolial degree 4, i.e. the highest exponent of the variable is 4
trinomial=> three terms
leading coefficient = the coefficient in front of the term with the highest exponent.
standard form=> ax^4 + bx^3 + c^2 + dx + e
Solution:
2x^4 + x^3 + 0x^2 + 0x + 30
which is equal to 2x^4 + x^3 + 30: this is a quartic trinomial with leading coefficient 2, written in standard form.
