The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
Read more about inverse functions at:
brainly.com/question/14391067
#SPJ1
Answer:not 100 % sure but I can write a slope intercept form equation, but not an inequality. I would need a picture of the graph to write an inequality.
First find slope: (y2 - y1)/(x2 - x1) Slope is 3
Choose a point then use point slope form y - y1 = m(x - x1) It is y - 1 = 3(x - 1)
Now simplify:
y - 1 = 3(x - 1)
y - 1 = 3x - 3
y = 3x - 2
y = 3x - 2
Step-by-step explanation:
Answer:
69
Step-by-step explanation:
Answer:
non-included
Step-by-step explanation:
A non included side of a polygon shares a side with only one angle of a pair of angles.
