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lubasha [3.4K]
3 years ago
12

WILL MARK BRAINLIEST! PLEASE HELP MEH!Use the relationship between the angles in the figure to answer the question. Which equati

on can be used to find the value of x? Drag and drop the equation into the box.
A) x=180−31+40
B)x=90−40
C)​​x=180−(31+40)
D)​​x=90−(31+40)

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
5 0
A straight line (or two rays in a  straight line) = 180o
to find x start with this equation
31 + x + 40 = 180 Now get all the numbers on the right.
(31 + 40) + x = 180
x = 180 - (31 + 40)
Only A or C can be correct. It is C, but you have to be very careful how you eliminate A
C <<<< answer.


x = 180 - 31 - 40 is the correct way to remove the brackets. 
x = 180 -  71
x = 109

There are better ways to do this particular question without using brackets.
Angelina_Jolie [31]3 years ago
3 0

Answer:

C. x=180^o-(31^o+40^o)  

Step-by-step explanation:

We have been given a figure of angles formed on a straight line.

Since we know that the angles on a straight line add up-to 180 degrees. Upon using this property we can set an equation as:

31^o+x^o+40^o=180^o

Let us subtract 40 and 31 degrees from both sides of our equation to solve to x.

31^o-31^o+x^o+40^o-40^o=180^o-31^o-40^o    

x=180^o-31^o-40^o

Upon factoring negative sign from right side of our equation we will get,

x=180^o-(31^o+40^o)

Therefore, the equation x=180^o-(31^o+40^o) can be used to find the value of x and option C is the correct choice.


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tia_tia [17]
To find the answer, let's first figure out what the formula is saying. Since we know Joel spent a total of $165, the right side of the formula represents the total while the left side is made up of the costs of the clothing. Now, since we know that he purchased 2 shirts, the 2y in the formula would represent the total cost of two shirts. Therefore, simply y would represent the price of a shirt.

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3 years ago
What is the differnce between ║-3║ and - 3.
Deffense [45]

Answer:

l-3l=3 and -3=-3

Step-by-step explanation:

The two bars mean you are finding the absolute value of a number. Absolute value is the distance from zero a number is. Since distance is always positive it basically just means take away the negative if there is one. For example,

l-7l=7 and l8l=8. So the difference is -3 is negative while l-3l is positive.

3 0
3 years ago
Read 2 more answers
Solve for the value of x in:<br> x^2+ 6x + 25 = 0
Julli [10]

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- \frac{3}{13}  +   \frac{2 \sqrt{79} }{13} i

3 0
3 years ago
Please help me with this math problem, urgent please help
wel

Answer:

  The slope is 4, and the y-intercept is -7.

Step-by-step explanation:

The slope-intercept form of the equation of a line is ...

  y = mx + b

where m is the slope, and b is the y-intercept.

Comparing this with the equation you are given, we see that ...

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The slope is 4, and the y-intercept is -7.

8 0
3 years ago
If c is the line segment connecting (x1,y1) to (x2,y2), show that the line integral of xdy-ydx=x1y2-x2y1......this is in a chapt
MatroZZZ [7]
Green's theorem doesn't really apply here. GT relates the line integral over some *closed* connected contour that bounds some region (like a circular path that serves as the boundary to a disk). A line segment doesn't form a region since it's completely one-dimensional.

At any rate, we can still compute the line integral just fine. It's just that GT is irrelevant.

We parameterize the line segment by

\mathbf r(t)=\langle x_1,y_1\rangle(1-t)+\langle x_2,y_2\rangle t
\implies\mathbf r(t)=\langle x_1+(x_2-x_1)t,y_1+(y_2-y_1)t\rangle

with 0\le t\le1. Then we find the differential:

\mathbf r(t)\equiv\langle x,y\rangle=\langle x_1+(x_2-x_1)t,y_1+(y_2-y_1)t\rangle
\implies\mathrm d\mathbf r\equiv\langle\mathrm dx,\mathrm dy\rangle=\langle x_2-x_1,y_2-y_1\rangle\,\mathrm dt

with 0\le t\le1.

Here, the line integral is

\displaystyle\int_{\mathcal C}x\,\mathrm dy-y\,\mathrm dx=\int_{\mathcal C}\langle-y,x\rangle\cdot\langle\mathrm dx,\mathrm dy\rangle
=\displaystyle\int_{t=0}^{t=1}\langle-y_1-(y_2-y_1)t,x_1+(x_2-x_1)t\rangle\cdot\langle x_2-x_1,y_2-y_1\rangle\,\mathrm dt
=\displaystyle\int_{t=0}^{t=1}(x_1y_2-x_2y_1)\,\mathrm dt
=(x_1y_2-x_2y_1)\displaystyle\int_{t=0}^{t=1}\,\mathrm dt
=x_1y_2-x_2y_1

as required.
4 0
4 years ago
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