All categories

2 years ago

Question 13

Mathematics

1 answer:

PtichkaEL [24]2 years ago

5 0

Answer:

B. 30x

D. x(45-15)

Step-by-step explanation:

The distributive property lets you factor out the common factor of x. The sum of coefficients can be simplified to a single coefficient.

45x -15x = x(45 -15) = 30x

You might be interested in

Given: ∠A is a straight angle. ∠B is a straight angle.

choli [55]

Given: ∠A is a straight angle. ∠B is a straight angle.

We need to Prove: ∠A≅∠B.

We know straight angles are of measure 180°.

So, ∠A and <B both would be of 180°.

It is given that ∠A and ∠B are straight angles. This means that both angles are of 180° because of the the definition of straight angles. Using the definition of equality, m∠A=m∠B . Finally, ∠A≅∠B by definition of congruent. 

7 0

3 years ago

Read 2 more answers

Please I really need help with this

ipn [44]

You would do 4-2= 2 then 8/2 =4 .. final answer being 4

4 0

3 years ago

Read 2 more answers

What is the equation of the coordinate A and B if they are (4,7), (6,3) respectively. What is the equation of the straight line.

Nesterboy [21]

Answer: y+2x=15

Step-by-step explanation:

Given

Two points A and B are (4,7) and (6,3) respectively

Using two-point form

$\Rightarrow \dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}$

Putting values

$\Rightarrow \dfrac{y-7}{x-4}=\dfrac{3-7}{6-4}\\\\\Rightarrow \dfrac{y-7}{x-4}=\dfrac{-4}{2}=-2\\\\\Rightarrow y-7=-2x+8\\\\\Rightarrow y+2x=15$

3 0

3 years ago

Write the function a a product of linear factor by grouping or using the x method or a combination of both

Sladkaya [172]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\sf Option \ A \ is \ correct .}}}$

<h3>Step-by-step explanation:</h3>

Given function to us is :-

$\bf \implies g(x) = x^2 - 9$

And we , need to write the function a a product of linear factor by grouping or using the x method or a combination of both . So let's factorise this ,

$\bf \implies g(x) = x^2 - 9 \\\\\bf\implies g(x) = x^2-3^2\\\\\bf\implies \boxed{\red{\bf g(x) = (x+3)(x-3) }}\:\:\bigg\lgroup \blue{\tt Using \ (a+b)(a-b) \ = a^2-b^2 }\bigg\rgroup$

I have also attached the graph of x²-9.

<h3>Hence option A is correct .</h3>

4 0

3 years ago

Part A: Consider the equation x + 7 = 16. Which number from the set {5, 7, 9, 11} makes the equation true?

wel

Part A: Substitute/plug in each number into the equation to see which number will make the equation true.

x + 7 = 16 Plug in 5 into "x"

5 + 7 = 16

12 = 16 5 doesn't make the equation true because it equals 12 not 16

x + 7 = 16 Plug in 7 into "x"

7 + 7 = 16

14 = 16 7 doesn't make the equation true because it equals 14 not 16

x + 7 = 16 Plug in 9 into "x"

9 + 7 = 16

16 = 16 9 makes the equation true because it equals 16

Part B: Plug in 9 into "x" in the inequality to see if it still makes it true.

x + 7 < 16 [x plus 7 is less than 16]

9 + 7 < 16

16 < 16 [16 is less than 16] The same number would not make the inequality true because 16 can't be less than itself.

To figure out which numbers satisfy the inequality, plug it into the inequality:

x + 7 < 16 Plug in 5 into "x"

5 + 7 < 16

12 < 16 5 does satisfy the inequality because 12 is less than 16

x + 7 < 16 Plug in 7 into "x"

14 < 16 7 does satisfy the inequality because 14 is less than 16

x + 7 < 16 Plug in 11 into "x"

11 + 7 < 16

18 < 16 11 doesn't satisfy the inequality because 18 isn't less than 16

3 0

2 years ago