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Masja [62]
2 years ago
14

Which expressions are equivalent to the expression below?

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
8 0

Given :-

  • -1/3 - ( -4 + 1/6 )

To Find :-

  • The expression that is equivalent to one of the choices given .

Solution :-

As we know that ,

→ (-) × (-) = (+)

→ (-) × (+) = (-)

→ (+) × (-) = (-)

→ (+) × (+) = (+)

On using these open the brackets ,

→ -1/3 - 1( -4 + 1/6 )

→ -1/3 - 1(-4) + -1(+1/6)

→ -1/3 (-)(-)(1* 4) (+)(-) (1*1/6)

On using now above stated rules ,

→ -1/3 +4 -1/6

Somewhat rearrange ,

→ 4 -1/3 -1/6

Take (-) as common,

→ 4 - (1/3 +1/6)

<u>Hence Option </u><u>(</u><u>d)</u><u> </u><u>&</u><u> </u><u>(f) </u><u>are</u><u> correct .</u>

I hope this helps.

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Which expression is equivalent to log Subscript w Baseline StartFraction (x squared minus 6) Superscript 4 Baseline Over RootInd
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Option b: 4 \log _{w}\left(x^{2}-6\right)-\frac{1}{3} \log _{w}({x^{2}+8}) is the correct answer.

Explanation:

The expression is \log _{w}\left(\frac{\left(x^{2}-6\right)^{4}}{\sqrt[3]{x^{2}+8}}\right)

Applying log rule, \log _{c}\left(\frac{a}{b}\right)=\log _{c}(a)-\log _{c}(b), we get,

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Again applying the log rule, \log _{a}\left(x^{b}\right)=b\cdot\log _{a}(x), we get,

4 \log _{w}\left(x^{2}-6\right)-\log _{w}(\sqrt[3]{x^{2}+8})

The cube root can be written as,

4 \log _{w}\left(x^{2}-6\right)-\log _{w}({x^{2}+8})^{\frac{1}{3} }

Applying the log rule, \log _{a}\left(x^{b}\right)=b\cdot\log _{a}(x), we have,

4 \log _{w}\left(x^{2}-6\right)-\frac{1}{3} \log _{w}({x^{2}+8})

Thus, the expression which is equivalent to \log _{w}\left(\frac{\left(x^{2}-6\right)^{4}}{\sqrt[3]{x^{2}+8}}\right) is 4 \log _{w}\left(x^{2}-6\right)-\frac{1}{3} \log _{w}({x^{2}+8})

Hence, Option b is the correct answer.

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Hope this helps :)
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