Answer:
20
Step-by-step explanation:
Just plug 3 into the equation for x:
6/3 + 2(3)^2
2 + 18
2 + 18 = 20
We have a three unknown, 4 equation homogeneous system. These always have at least (0,0,0) as a solution. Let's write the equations, one column at a time.
1a + 0b + 0c = 0
-1a + 1b +0c = 0
0a - 1b + c = 0
0a + 0b + -1 c = 0
We could do row reduction but these are easy enough not to bother.
Equation 1 says
a = 0
Equation 4 says
c = 0
Substituting in the two remaining,
-1(0) + 1b + 0c = 0
b = 0
0(0) - 1b + 0 = 0
b = 0
The only 3-tuple satisfying the vector equation is (a,b,c)=(0,0,0)
3 1/2 or 7/2
keep the 3 yards and round the 4/5 to half a yard or 1/2 and just in case turn into a improper fraction
Answer:
Step-by-step explanation:
Vertex form of a quadratic equation;
Vertex of the parabolas (h, k)
The vertex of the parabola is either the minimum or maximum of the parabola. The axis of symmetry goes through the x-coordinate of the vertex, hence h = -3. The minimum of the parabola is the y-coordinate of the vertex, so k= 7. Now substitute it into the formula;
Now substitute in the given point; ( -1, 9) and solve for a;
Hence the equation in vertex form is;
In standard form it is;
Plan A: 30 + 0.01m
Plan B: 20 + 0.05m
in order for 2 plans cost the same, both need to be equal
so should be
20 + 0.05m = 30 + 0.01m
answer is D. last one
20 + 0.05m = 30 + 0.01m
