The image of the question is attached below.
Given:
m∠DAC = 20° and m∠BCA = 30°
m∠ABC = 90° and m∠CDA = 90°
To find:
The value of x and y.
Solution:
In right triangle ABC,
m∠BAC = x° + 20°
Sum of the interior angles of a triangle = 180°
m∠BAC +m∠ABC + m∠BCA = 180°
x° + 20° + 90° + 30° = 180°
x° + 140° = 180°
Subtract 140° from both sides.
x° + 140° - 140° = 180° - 140°
x° = 40°
In right triangle ADC,
m∠ACD = y° + 30°
Sum of the interior angles of a triangle = 180°
m∠ACD +m∠CDA + m∠DAC = 180°
y° + 30° + 90° + 20° = 180°
y° + 140° = 180°
Subtract 140° from both sides.
y° + 140° - 140° = 180° - 140°
y° = 40°
The value of x is 40 and y is 40.
Answer:
6m
Step-by-step explanation:
i am not sure
Answer:
3/8
Step-by-step explanation:
0.75/2=x/1. Solve proportion: 0.75*1/2=x x=0.375 or 3/8.
Hope this helps plz mark brainliest :D
Answer:
14 km
Step-by-step explanation:
6 km in the afternoon
x km in the morning
6= x- 25%
6= 0.75x
x= 6/0.75
x= 8 km
total 6+8= 14 km
Answer:
Step-by-step explanation:
h(g(x))
g(x)= 3x + 1
h(3x + 1) = 4(3x + 1) = 12x + 4