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3 years ago

last week tom had 28 dollars. He washed cars over the weeknd and now has 91 dollars. How much money did he make washing cars?

Mathematics

2 answers:

koban [17]3 years ago

6 0

Answer:

63 dollars

Step-by-step explanation:

91-28 is 63. If the money that he had already in the previous week is removed from the total of money he has this week then he would have earned 63 dollars.

Allisa [31]3 years ago

3 0

Answer:63

Step-by-step explanation:

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I'm solving systems and I don't understand how to do it pls helpp

kaheart [24]

Answer:

Use the process of elimination. I'll only do one example since you have 4.

Step-by-step explanation:

Let's do the first question.

2x-3y=-11

2x+y=9

Our goal here is to be left with one variable to solve, this way we can use the answer for that variable to find the other. A.K.A only find X to plug into the equation to find Y. To do this, we'll use the process of elimination, in which we need to cancel out a variable.

X seems the easiest here. To cancel 2 (in the top equation), you need to have a -2. And that -2 needs to be the x coefficient in the 2nd equation, in order for us to "cancel" it out. To get -2, you multiply 2 by -1.

-1(2x+y)= -1(9)

Note that whatever you do to one side, you need to do it to both sides! Hence, why I also multiplied 9 by -1. You should now be left with:

-2x -y = -9

Now, we cancel out the positive 2 and -2 from both equations by adding the two equations.

2x-3y= 11

-2x-y=-9

X cancels out, so we're left with -4y=-20. Solve for Y, which is 5.

-4y=-20

y=5

Now that you have the Y value, plug it into any of the two equations to find your X value.

2x-3y=11

2x-3(5)=11

2x-15=11

2x=26

x=13

And voilah! Our Y value is 5, and our X value is 13.

It's pretty simple once you understand what's going on. All that we did was to cancel out one variable (either X or Y) in the two equations so that we're left with only one variable to solve. If we cancel out X, we only need to solve for Y. You do this by manipulating one of the two equations (doesn't matter which one). Once you find either X or Y, all you need to is to plug it into one of the original equations. Then, you'll have both X and Y.

And that my friend, is the process of elimination. Good luck!

8 0

3 years ago

Read 2 more answers

Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans

zloy xaker [14]

Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the perimeters of the quadrilaterals the same is 2.

Part B:

The area of the square is given by

$Area=(x+4)^2=x^2+8x+16$

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

$x^2+8x+16=6x+8 \\ \\ \Rightarrow x^2+8x-6x+16-8=0 \\ \\ \Rightarrow x^2+2x+8=0 \\ \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2} \\ \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2} \\ \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}$

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.

7 0

4 years ago

Missing letter H, I,I, K, J,M, _,O,L,W

krok68 [10]

F and U and C and K and then finally U

3 0

3 years ago

Shawndra said that it is not possible to draw a trapezoid that is a rectangle, but it is possible to draw a square that is a rec

ICE Princess25 [194]

Shawndra is correct

She made two statements, and both are true:

1. It is not possible to draw a trapezoid that is a rectangle.

This is true because a trapezoid is a quadrilateral that has exactly one pair of parallel sides, whereas a rectangle is a parallelogram (i.e. it has two pairs of parallel sides)

2. It is possible to draw a square that is a rectangle.

This is true because a rectangle refers to any parallelogram with right angles. A square is also a parallelogram (has two pairs of opposite sides) with right angles. In fact, all squares are rectangles; only that they are a special kind of rectangle, where all the sides are equal in length.

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4 years ago

Read 2 more answers

Hi i need help below thank you 32 POINTS

lara [203]

A = (pi) * r*2
(pi) = 3.14
r = d/2.....r = 17/2 or 8.5

A = 3.14 * 8.5^2
A = 3.14 * 72.25
A = 226.86 rounds to 226.9 m^2 <==

6 0

3 years ago

last week tom had 28 dollars. He washed cars over the weeknd and now has 91 dollars. How much money did he make washing cars?​

last week tom had 28 dollars. He washed cars over the weeknd and now has 91 dollars. How much money did he make washing cars?