4÷(6-(8÷2))=2
Do the order of operations, and the end value will be 2.
Do you understand how I got that? Good luck by the way!
When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] /
<span>
<span>
<span>
1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) =
<span>
<span>
<span>
0.96374829001368
Angle A = 15.475
Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
</span><span>sin(B) = 0.26682 * 43 / 27
sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
Remember the arc sine (<span>0.424935555555) also equals </span>
<span>
<span>
<span>
154.85
</span></span></span>Finally, calculating the third angle is quite easy
Angle C = 180 - Angle (A) - Angle(B)
Angle C = 180 - 15.475 - 154.85
Angle C = 9.675
Source:
http://www.1728.org/trigtut2.htm
Hello!
You have to find the probability of getting a 2
This is a 1/6 chance
Then you have to find the chance of getting a number greater than 2
This is a 4/6 chance
To find the chance of these happening at the same time you multiply these together
1/6 * 4/6 = 1/9
There is a 1/9 chance
Hope this helps!
Answer:
x = 1
Step-by-step explanation:
Step 1: Write equation
9 - 2x = 7x
Step 2: Solve for <em>x</em>
<u>Add 2x on both sides:</u> 9 = 9x
<u>Divide both sides by 9:</u> x = 1
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
9 - 2(1) = 7(1)
9 - 2 = 7
7 = 7
Answer:
P(red) = .3
P(yellow) = .3
75 cubes in the box
Step-by-step explanation:
The probability has to add to 1
Since the number of red cubes equals the number of yellow cubes the probability has to be the same
.4 + x+x = 1
.4 +2x = 1
2x = 1-.4
2x = .6
Divide by 2
x = .6/2
x = .3
P(red) = .3
P(yellow) = .3
We know that
P(blue) = .4 = number of blue cubes/ total number of cubes
.4 = 30/total
total = 30/.4
total = 75
