Ask question

Ask question

All categories

2 years ago

12

Ali, Ben, and Cliff plant seedlings in their neighborhood park. Ali plants 40% of the total number of seedlings, Ben plants 45%

of the total number of seedlings, and Cliff plants the rest of the seedlings. If Cliff plants 87 seedlings, how many seedlings do the three boys plant altogether?

1 answer:

Juli2301 [7.4K]2 years ago

7 0

Answer:

580 seedlings altogether.

Step-by-step explanation:

Given that,

Ali plants 40% of the total number of seedlings, Ben plants 45% of the total number of seedlings, and Cliff plants the rest of the seedlings. Cliff plants 87 seedlings.

The percentage of the seedling planted by Cliff = 100% - 45% - 40% = 15%

<em>Let x = the total number of seedlings</em>

<em /> $15\%\ of\ x=87\\\\x=\dfrac{87\times 100}{15}\\\\x=580$

Hence, three boys plant 580 seedlings altogether.

You might be interested in

The cube shown below holds 64 cubic centimeters of water. Label the dimensions of the cube.

LekaFEV [45]

The measure of the side of the cube is <u>4 centimeters</u>, and its dimensions are <u>4 centimeters × 4 centimeters × 4 centimeters</u>.

A cube is a solid object in three dimensions with six square faces that all have the same length of sides. Six square faces, eight vertices, and twelve edges make up the form. Since the 3D figure is a square with equal-length sides, the length, breadth, and height of a cube are all the same measurement. The edge, which is regarded as the bounding line of the edge, is the shared border between the faces of a cube. Each face is connected to four vertices and four edges, three vertices are connected to three edges and three faces, and two vertices and two edges are in contact to create the structure.

A cube's volume is the amount of space it takes up. Finding the cube of the cube's side length will provide the volume of the cube.

Cube volume equals a³, where a is the length of a cube's side.

In the question, we are asked to find the dimensions of the cube, given that it holds 64 cubic centimeters of water.

If the cube holds 64 cubic centimeters of water, then we know that the cube's volume is 64 cubic centimeters.

Assuming the length of the side of the cube to be centimeters, we can say that a³ = 64, knowing that a cube volume equals a³, where a is the length of a cube's side.

Thus, we have a³ = 64,

or, a = ∛64,

or, a = 4.

Thus, the measure of the side of the cube is <u>4 centimeters</u>, and its dimensions are <u>4 centimeters × 4 centimeters × 4 centimeters</u>.

Learn more about the volume of a cube at

brainly.com/question/1972490

#SPJ9

4 0

1 year ago

Urgent please help answer 10 a thanksssss

rjkz [21]

There are two pairs of equal matching angles. One pair is marked, the pair of 15 degree angles. The other pair are the vertical angles formed by the intersecting lines.

5 0

2 years ago

James is working out and has decided that for every 10 sit-ups he does, he needs to do 4 push-ups. If he does 120 sit-ups, how m

mario62 [17]

Answer:

480 is the answer

Step-by-step explanation:

120x4 is 480

4 0

2 years ago

6. What is the surface area of the cone? Use

Lostsunrise [7]

It would be 20ft have a great day

4 0

2 years ago

Read 2 more answers

Find the function y1 of t which is the solution of 121y′′+110y′−24y=0 with initial conditions y1(0)=1,y′1(0)=0. y1= Note: y1 is

strojnjashka [21]

Answer:

Step-by-step explanation:

The original equation is $121y''+110y'-24y=0$ . We propose that the solution of this equations is of the form $y = Ae^{rt}$ . Then, by replacing the derivatives we get the following

$121r^2Ae^{rt}+110rAe^{rt}-24Ae^{rt}=0= Ae^{rt}(121r^2+110r-24)$

Since we want a non trival solution, it must happen that A is different from zero. Also, the exponential function is always positive, then it must happen that

$121r^2+110r-24=0$

Recall that the roots of a polynomial of the form $ax^2+bx+c$ are given by the formula

$x = \frac{-b \pm \sqrt[]{b^2-4ac}}{2a}$

In our case a = 121, b = 110 and c = -24. Using the formula we get the solutions

$r_1 = -\frac{12}{11}$

$r_2 = \frac{2}{11}$

So, in this case, the general solution is $y = c_1 e^{\frac{-12t}{11}} + c_2 e^{\frac{2t}{11}}$

a) In the first case, we are given that y(0) = 1 and y'(0) = 0. By differentiating the general solution and replacing t by 0 we get the equations

$c_1 + c_2 = 1$

$c_1\frac{-12}{11} + c_2\frac{2}{11} = 0$ (or equivalently $c_2 = 6c_1$

By replacing the second equation in the first one, we get $7c_1 = 1$ which implies that $c_1 = \frac{1}{7}, c_2 = \frac{6}{7}$ .

So $y_1 = \frac{1}{7}e^{\frac{-12t}{11}} + \frac{6}{7}e^{\frac{2t}{11}}$

b) By using y(0) =0 and y'(0)=1 we get the equations

$c_1+c_2 =0$

$c_1\frac{-12}{11} + c_2\frac{2}{11} = 1$ (or equivalently $-12c_1+2c_2 = 11$

By solving this system, the solution is $c_1 = \frac{-11}{14}, c_2 = \frac{11}{14}$

Then $y_2 = \frac{-11}{14}e^{\frac{-12t}{11}} + \frac{11}{14} e^{\frac{2t}{11}}$

c)

The Wronskian of the solutions is calculated as the determinant of the following matrix

$\left| \begin{matrix}y_1 & y_2 \\ y_1' & y_2'\end{matrix}\right|= W(t) = y_1\cdot y_2'-y_1'y_2$

By plugging the values of $y_1$ and

We can check this by using Abel's theorem. Given a second degree differential equation of the form y''+p(x)y'+q(x)y the wronskian is given by

$e^{\int -p(x) dx}$

In this case, by dividing the equation by 121 we get that p(x) = 10/11. So the wronskian is

$e^{\int -\frac{10}{11} dx} = e^{\frac{-10x}{11}}$

Note that this function is always positive, and thus, never zero. So $y_1, y_2$ is a fundamental set of solutions.

8 0

2 years ago