I conclude that the sum will be even because any even number can be represented by 2n where n is a whole number and even numbers are 2 apart, so the sum of the first 15 are 2n+2(n+1)+2(n+2) etc until we get to 2(n+14) we can undistribute the 2 from all of them and get 2(n+n+1+n+2...n+14) and we are sure that whatever is in the parenthasees is a whole number because whole+whole=whole therefor, the sum is even
if you did want to find the sum then an=2n the 15th even number is 30 the first is 2 S15=15(2+30)/2=15(32)/2=15(16)=240 which is even
