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PtichkaEL [24]
3 years ago
10

Marc puts 28 liters of water into a tub and 6 liters of water into a bucket. Then, he pours both containers into a tank.

Mathematics
2 answers:
hjlf3 years ago
7 0
What is the question asking for?
lions [1.4K]3 years ago
3 0

Answer:

34

Step-by-step explanation:

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How do you type 40:16 ratio in to simplest form
Blizzard [7]
5:2
because you need to divide them by 8 to get to simplest form
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3 years ago
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At 1:00 pm the water level in a pool is 13 inches. At 1:30pm the water level is 18 inches. At 2:30pm the water level is 28 inche
SashulF [63]
From the given question we come to know of certain number of facts and they are:
At 1:00 PM the water level of the pond was = 13 inches
At 1:30 PM the water level of the pond was = 18 inches
At 2:30 PM the water level of the pond was = 28 inches
From the above given facts we can easily find the amount of water changing every half an hour.
Amount of increase in water from 1:00PM to 1:30 PM = (18 - 13) inches
                                                                                       = 5 inches
Amount of increase in water level from 1:30PM to 2:30PM = (28 -18) inches
                                                                                             = 10 inches
From the above two deductions we can come to the conclusion the the constant rate of change in water level is 5 inches for every half an hour.
4 0
3 years ago
Read 2 more answers
Juan fode his bike 2/3 mile to school,1/3 mile to the library,2/3 mile home far did he ride altogether
Viktor [21]

Answer:1 2/3

Step-by-step explanation:

2/3+1/3+2/3=5/3=1 2/3

7 0
3 years ago
If the 13th and 38th terms of an arithmetic sequence are -53 and -128,
love history [14]

9514 1404 393

Answer:

  -2018

Step-by-step explanation:

The n-th term is ...

  an = a1 +d(n -1)

So, the given terms are ...

  -53 = a1 +12d

  -128 = a1 +37d

Subtracting the first from the second gives ...

  (a1 +37d) -(a1 +12d) = (-128) -(-53)

  25d = -75

  d = -3

The 668th term will be ...

  a668 = a1 +d(668 -1) = a1 +667d = (a1 +37d) +630d

  a668 = -128 +630(-3) = -128 -1890 . . . . substitute for a38

  a668 = -2018

7 0
2 years ago
Ef/4 E=3 F=4 What is the answer?Simplify.
sesenic [268]
First substitute
(3)(4)/4
then simplify.
12/4
then solve
3
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3 years ago
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