Step-by-step explanation:
In triangle ADE:
sum of all angles is 180.
3x-10+58+42=180
3x+90=180
3x=180-90
3x=90
x=90/3
x=30
As line DA and CB are parallel:
angle D=angle C
angle y=58
In angle BCE, sum of angles is 180.
z+58+42=180
z+100=180
z=180-100
z=80
Basically you’re multiplying them both
(x^3 + 2x - 1)(x^4 - x^3 + 3)
so you need to make sure you multiply each one, if you do it right, you should end up with
x^7 - x^6 + 3x^3 + 2x^5 - 2x^4 + 6x -x^4 +x^3 -3
simplify by adding like terms
x^7 - x^6 + 2x^5 - 3x^4 + 4x^3 + 6x - 3
your answer would be the third option
Solution:
As given Square L M NO is dilated by a scale factor of two about the center of the square to create square L'M'N'O'.
Original line of Dilation = Along P Q
New Dilated line = P'Q'
As scale factor > 1
1. Image Size > Pre image size
2. The two images will be similar.
3. Length of Dilated Line P' Q' = 2 × Length of PQ
As you can see from the diagram drawn below, Dilated line P'Q' will contain the point P and Q.
All four points P,Q,Q',P' are collinear , lie in the same line.
Option (2) dilated line P'Q' will contain the points P and Q is true.
The possibile answer is 10 ÷ 6 = 1.6