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nordsb [41]
4 years ago
6

Select the correct answer.

Mathematics
1 answer:
kondaur [170]4 years ago
5 0

Answer:

D

Ur welcome sir

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Two bags of cereal are packed in a box. The total weight of the box and the two bags of cereal is 58.00 ounces. One bag of cerea
blsea [12.9K]

Answer:

add the amount of the bags. you will end up with 38.70 Oz. the subtract the number from the total and you ger 19.30 Oz. the box weighs 19.30 oz.

6 0
2 years ago
Blake is a songwriter who collects royalties on his songs whenever they are played in a commercial or a movie. Blake will earn $
Mrac [35]

Answer:

It was played in 3 movies and in 10 commercials.

Step-by-step explanation:

110 times 3 = 330

530 minus 330 = 200

200 divided by 20 = 10

3 0
3 years ago
Multiply and simplify (4x-2)(3x^2-2x+1) Write answer in standard form
hjlf

Answer:

<h3>12<em>x</em>^3 - 14<em>x</em>^2 + 8<em>x</em> - 2</h3>

7 0
2 years ago
Read 2 more answers
2) A product originally costs $125. If the product goes on sale for 20% off, and then goes on sale for an additional 30% off, wh
alukav5142 [94]
To do these, always convert the percents to decimals, so you can subtract it from 1. Remember, 1 is the whole. When you subtract the part that's taken off, you are left with what you have to pay. If you have 20% off of $100, then you are paying for 80% of $100. **of means to multiply** so you would multiply: 0.8X100, which would be $80.

First, multiply 125x0.8

Multiply that answer by 0.7

You should get B. $70

3) multiple 22.90x0.93

You should get D
7 0
3 years ago
Read 2 more answers
Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
Margaret [11]
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
 
Distance traveled by car A =x,  (when the car B is at the same distance from the start line)
time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
x=15(t-3)

We solve this system of equations:

10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9

t-3=9-3=6

x=10 t=10 (9)=90

Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
8 0
3 years ago
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