Initial velocity of John's car (V1) = 0 miles per hour
Final velocity of John's car (V2) = 45 miles per hour
Time taken for acceleration = 45 seconds
Then
Acceleration = (V2 - V1)/Time taken
= (45 - 0)/15 miles per hour per second
= 45/15 miles per hour per second
= 3 miles per hour per second.
So the approximate rate of change in the miles per hour that John's car accelerated is 3 miles per hour per second. The correct option among all the options given in the question is option "A".
Answer:
True. See explanation below
Step-by-step explanation:
Previous concepts
Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".
The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"
If we assume that we have
groups and on each group from
we have
individuals on each group we can define the following formulas of variation:
And we have this property
The degrees of freedom for the numerator on this case is given by
where k represent the number of groups.
The degrees of freedom for the denominator on this case is given by
.
And the total degrees of freedom would be
And the we can find the F statistic
Answer:
-18
Step-by-step explanation:
18/3=6
6/ -2/6
=6* 6/-2
=-18