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marishachu [46]
3 years ago
7

Tim has completed five math problems and 13 minutes if he continues at the same rate how long will it take him to finish 20 prob

lems
Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0

Answer:

52 minutes

Step-by-step explanation:

it takes him 13 minutes to complete 5 so if he wants  to do 20 problems  do 20 divided by 5 (4) then do 13 times 4=52

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Solve the quadratic equation by factoring: 15x^2+4x-4=0
joja [24]
We can factor by grouping. To do so, we multiply the leading coefficient with the constant at the end. In other words, a times c (ax^2 + bx + c).

15*-4 = -60

Now we need to split the b term into two pieces that multiply to -60 and add to 4.

-6 and 10 will work.

Now group one part of b with the 15x^2 and the other part with -4.

(15x^2 + 10x) + (-6x - 4)

Now factor both terms.

5x(3x+2) - 2(3x+2)

3x+2 is one of our factors and 5x-2 is the other.

(3x+2)(5x-2)=0

Now just find the zeros.

3x+2 = 0
3x = -2
x = -2/3

And

5x-2 = 0
5x = 2
x = 2/5

So the answer is x = -2/3 and x = 2/5






7 0
3 years ago
WILL MARK BRAINLEIST!! Each figure is composed of large squares and small squares. The side length of the
julsineya [31]

9514 1404 393

Answer:

  A. x² -4

  B. 2x² +8

Step-by-step explanation:

The area of a square is the square of the side lengths. That means the area of each large square is x², since it has a side length of x.

__

A. The area of 4 small squares is subtracted from the area of the large square to find the shaded area:

  x² -4×1² = x² -4 . . . area of Figure A

__

B. The area of two small squares is added to the area of two large squares to find the shaded area:

  2x² +2×2² = 2x² +8 . . . area of Figure B

5 0
3 years ago
Suppose that contamination particle size (in micrometers) canbe modeled as
asambeis [7]

Answer:

c) 2

d) 0.96

Step-by-step explanation:

We are given the following in the question:

f(x) = 2x^{-3}, x > 1\\~~~~~~~= 0, x \leq 1

a) probability density function.

\displaystyle\int^{\infty}_{\infty}f(x) dx = 1\\\\\displaystyle\int^{\infty}_{-\infty}2x^{-3}dx = 1\\\\\displaystyle\int^{\infty}_{1}2x^{-3}dx\\\\\Rightarrow \big[-x^{-2}\big]^{\infty}_1\\\\\Rightarrow -(0-1) = 1

Thus, it is a probability density function.

b) cumulative distribution function.

P(X

c) mean of the distribution

\mu = \displaystyle\int^{\infty}_{-\infty}xf(x) dx\\\\\mu = \int^{\infty}_12x^{-2}dx\\\\\mu = (-\frac{2}{x})^{\infty}_{1}\\\\\mu = 2

d) probability that the size of random particle will be less than 5 micrometers

P(X

4 0
2 years ago
What is the slope of the linear function above? Write any fractions as improper fractions, using a '/'. (PLEASE HELP ME)
aliina [53]
-3/2
Down 3
Right 2
As an improper fraction it would be -1 1/2
8 0
2 years ago
Read 2 more answers
4х – 9у – 2 = 0 <br>12х - 5у + 38 = 0 <br>answer in x and y intercept​
garri49 [273]

Answer:

x=5

y=2

Step-by-step explanation:

-3(4х – 9у – 2 = 0)

=-12x+27y+6

12х - 5у + 38    

-12x+27y+6

22y=44

y=2

x:

4x-9(2)-2=

=4x-20

4x=20

x=5

3 0
3 years ago
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