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Ivan
3 years ago
10

Am I do this correctly?

Mathematics
1 answer:
love history [14]3 years ago
4 0

You have the right idea. You multiply the exponents. However, you did not multiply the denominators 6 and 6 to get 36

So you should have 12/36 reducing to 1/3 as your final exponent

Therefore, the answer is 6^(1/3) which is the same as the cube root of 6

Side note: you don't need to turn 2/3 and 1/2 into fractions with a denominator of 6. You can multiply straight across and simplify

(2/3)*(1/2) = (2*1)/(3*2) = 2/6 = 1/3

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Since it is a terminating decimal, 4.9 is rational?
Rus_ich [418]

Answer:

Yes it is because it's terminating.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Type the correct answer in each box. Spell all words correctly, and use numerals instead of words for numbers. If necessary, use
sweet [91]

Answer:

54 in

Step-by-step explanation:

9 inches x 6 inches

5 0
3 years ago
The probability of an economic decline in the year 2020 is 0.23. There is a probability of 0.64 that we will elect a republican
olasank [31]

Answer:

1) D and R are NOT independent events

2) The probability of electing a Republican president and an economic decline in 2020 is 0.224

3) If we experience an economic decline in 2016, the probability that a Republican president will have been elected in 2020 is 0.9739

4) the probability of economic decline or a Republican president elected in 2020 or both is 0.646

Step-by-step explanation:

Let "D" represent the event of an economic decline, and "R" represent the event of election of a Republican president

Given that;

P(D) = 0.23

P(R) = 0.64

Conditional P(D | R) =  0.35

1) Are R and D independent events?

we know that two events A & B are independent events if; P(B | A) = P(B)

here, P(D | R) =  0.35 and P(D) = 0.23

so; P(D | R) ≠ P(D)

Therefore D and R are NOT independent events

2) The probability of electing a Republican president and an economic decline in 2020;

we know that;

P(D | R) = P(D ∩ R) / P(R)

we substitute

0.35 = P(D ∩ R) / 0.64

P(D ∩ R) = 0.35 × 0.64

P(D ∩ R)  = 0.224

Therefore, The probability of electing a Republican president and an economic decline in 2020 is 0.224

3) If we experience an economic decline in 2016, what is the probability that a Republican president will have been elected in 2020?

P(R | D) = P(D ∩ R) / P(D)

we substitute

P(R | D) = 0.224 / 0.23

P(R | D) = 0.9739

Therefore, If we experience an economic decline in 2016, the probability that a Republican president will have been elected in 2020 is 0.9739

4) the probability of economic decline or a Republican president elected in 2020 or both

P(D ∪ R) = P(D) + P(R) - P(D ∩ R)

we subtitute

P(D ∪ R) = 0.23 + 0.64 - 0.224

P(D ∪ R)  = 0.646

Therefore, the probability of economic decline or a Republican president elected in 2020 or both is 0.646

6 0
3 years ago
Look/read the picture
SIZIF [17.4K]

Answer:

6 inches

Step-by-step explanation:

please pa heart and rate po

4 0
3 years ago
Read 2 more answers
Please help picture shown and show workkkk
tankabanditka [31]
1)
Area of largest circle - 2 * Area of one smaller circle = Area of the shaded region

AE = diameter of large circle = 48cm
radius of larger circle = diameter / 2 = 48cm / 2 = 24cm

4 circles fit across the diameter of the circle, so the diameter of the larger circle = 4 * diameter of the smaller circle
diameter of larger circle = 48cm = 4 * diameter of the smaller circle
diameter of the smaller circle = 48cm / 4 = 12cm
radius of smaller circle = diameter / 2 = 12cm / 2 = 6cm

Area of a circle = pi * r^2

Now plug the circle area equation into the first equation:
A_{shaded}=A_{l} - 2*A_{s}\\\\A_{shaded}=[\pi (r_{l})^{2}]-2*[\pi (r_{s})^{2}]\\\\A_{shaded}=[\pi (48cm)^{2}]-2*[\pi (6cm)^{2}]\\\\A_{shaded}=2304\pi-72\pi\\\\Area\ of\ shaded\ region\ is\ 2232\pi.


2)
Area of the shaded region = 2/7 * Area of the smaller circle
Area of the unshaded region = Area of larger circle + Area of smaller circle - Area of shaded region * 2
A_{unshaded}=[\pi (r_{1})^{2}]+[\pi (r_{2})^{2}]-2*[\pi (r_{2})^{2}]*\frac{2}{7}\\\\A_{unshaded}=[\pi (10cm)^{2}]+[\pi (7cm)^{2}] -\frac{4}{7}[\pi (7cm)^{2}]\\\\A_{unshaded}=100\pi\ cm^{2}+49\pi\ cm^{2}-\frac{4*49\pi\ cm^{2}}{7}\\\\A_{unshaded}=149\pi\ cm^{2}-(4*7*\pi\ cm^{2})\\\\A_{unshaded}=149\pi\ cm^{2}-28\pi\ cm^{2}\\\\\\A_{unshaded}=121\pi\ cm^{2}
3 0
4 years ago
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